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2 years ago

8

HELPPPPP PLEASE! !!!

2 answers:

Pepsi [2]2 years ago

6 0

Answer:

5/7

Step-by-step explanation:

An easy way to find the biggest fraction is to divide the numerator by the dominator to turn it into a decimal, a more complexed way would be to do much more work and turn all fractions into having the same dominator

5/7 = 0.714

2/12 = 0.166

15/40 = 0.375

8/20 = 0.4

RoseWind [281]2 years ago

5 0

Answer:

5/7 is the largest

Step-by-step explanation:

$\frac{5}{7}$ is the largest fraction because it is the closest to the denominator 7. Think of it as a pizza that for some reason is cut into seven pieces, if you ate 5 pieces you ate most of the pizza. However if you cut this pizza into 12 slices and only ate 2 well you almost didn't eat much and you can continue this idea of pizza for 15/40 and 8/20.

You can also divide these numbers to see the fraction as decimals but it's not necessary.

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3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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