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3 years ago

11

What is 1080 divided by 45

1 answer:

liraira [26]3 years ago

6 0

Answer:

24

Step-by-step explanation:

thats the answer

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Name two lines that intersect and the point where they intersect ?

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Line ae intersects at point b
line cb intersects at point b

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3 years ago

More than half of the students were excited about the project. In fact, were excited. If 10 students were not

alina1380 [7]

Answer:1/2 divided by 10

Step-by-step explanation:

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3 years ago

PLS HELP DUE SOON GIVING BRAINLIEST

kupik [55]

102 and 102

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3 years ago

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Order the numbers in each list from least to greatest. 0, |-14|, 13 , -12, |-16|, 17

jeka57 [31]

Here is your answer:

In order to find the answer you must first find the absolute value of each number, then order them from least to greatest.

$0 = 0$
$I-14I = 14$
$13 = 13$
$-12 = 12$
$I-16I=16$
$17 = 17$
Now least to greatest:
$-12,0,13,14,16,17$

Therefore the answer is "-12,0,13,14,16,17."

Hope this helps!

4 0

3 years ago

Read 2 more answers

Given the recursive formula for an arithmetic sequence find the common difference and the 52nd term

Mice21 [21]

Answer:

Common difference(d) $a_{52}$

(21) -10 -548

(22) -7 -323

(23) 10 547

(24) -100 -5118

Step-by-step explanation:

Let the common difference be denoted by 'd'.

Also the nth difference of an arithmetic sequence is given by: $a_{n}=a_{1}+(n-1)\times d$

(21)

We are given a recursive formula as:

$a_{n}=a_{n-1}-10$

The first term is given by:

$a_{1}=-38$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-10$

The nth term of an arithmetic sequence is given by:

$a_{n}=a_{1}+(n-1)\times d$

Here $a_{1}=-38$ and $d=-10$ .

Hence, $a_{52}=-38+(52-1)\times (-10)$

Hence, $a_{52}=-548$

(22)

$a_{n}=a_{n-1}-7$

$a_{1}=34$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-7$

Here $a_{1}=34$ and $d=-7$ .

Hence, $a_{52}=34+(52-1)\times (-7)$

Hence, $a_{52}=-323$

(23)

$a_{n}=a_{n-1}+10$

$a_{1}=37$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=10$

Here $a_{1}=37$ and $d=10$ .

Hence, $a_{52}=37+(52-1)\times (10)$

Hence, $a_{52}=547$

(24)

$a_{n}=a_{n-1}-100$

$a_{1}=-18$

The common difference for an arithmetic sequence is given by:

$a_{n}-a_{n-1}$

Hence, here we have the common difference as:

$d=-100$

Here $a_{1}=-18$ and $d=-100$ .

Hence, $a_{52}=-18+(52-1)\times (-100)$

Hence, $a_{52}=-5118$

5 0

4 years ago