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Zigmanuir [339]
4 years ago
11

Using the graph of f(x)=log2^X below, approximate the value of y in the equation 2^2y=3 y=4.01. y=.79. y=1.58. y=0.47

Mathematics
1 answer:
Citrus2011 [14]4 years ago
5 0
The answer would be y=.79
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