Using the graph of f(x)=log2^X below, approximate the value of y in the equation 2^2y=3 y=4.01. y=.79. y=1.58. y=0.47
1 answer:
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For this case, the first thing to do is to graph the following ordered pairs:
(-6, -1)
(-3, 2)
(-1,4)
(2,7)
We observe that the graph is a linear function with the following equation:
y = x + 5
Note: see attached image.
Answer:
The function that best represents the ordered pairs is:
y = x + 5
(-6, -1)
(-3, 2)
(-1,4)
(2,7)
We observe that the graph is a linear function with the following equation:
y = x + 5
Note: see attached image.
Answer:
The function that best represents the ordered pairs is:
y = x + 5