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3 years ago

What is 10 times something equal 24

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

6 0

Answer:

2.4

Step-by-step explanation:

An easy way to find this is via division.

24 ÷ 10 = 2.4 | therefore,

2.4 × 10 = 24

vladimir2022 [97]3 years ago

3 0

Answer:

2.4

Step-by-step explanation:

"something" = x

10x = 24

divide both sides by 10

10x/10 = 24/10

x = 2.4

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3 years ago

Linear Relationships Study Guide 1.) Select all the equations for which (-6, -1) is a solution. Show your work to prove that eac

TiliK225 [7]

we have point (-6, - 1)

Now we will put these points in each equation,

y = 4x +23

put x = -6 and y = -1

-1 = 4 (-6) +23

-1 = -24 + 23

-1 = -1

LHS = RHS, so this equation has (-6 , -1) as solution.

y = 6x

put x = -6 and y = -1

-1 = 6 (-6)

-1 not= -36

LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,

y = 3x - 5

put x = -6 and y = -1

-1 = 3 (-6) - 5

-1 = -18 - 5

-1 not= -23

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y= 1/6 x

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6 0

1 year ago

5/8 divided by 3/4 what the answer

charle [14.2K]

Answer:

20/24. Simplified answer is 5/6

Step-by-step explanation:

5/8 divided by 3/4 is the same as asking 5/8 times 4/3

When dividing a number by a fraction, you can always just multiply by the fraction with its numerator and denominator switched!

So, now we have 5/8 times 4/3

Step 1: Multiply the numerators together. 5 times 4 = 20

Step 2: Multiply the denominators together. 8 times 3 = 24

Step 3: Put the new numerator over the new denominator. 20 over 24 is 20/24

Step 4: Simplify the fraction if necessary. 20 and 24 share a common factor of 4, so divide both the numerator and denominator by 4.

20 divided by 4 = 5

24 divided by 4 = 6

So, 20/24 is equal to 5/6.

7 0

3 years ago

Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graph

diamong [38]

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines : y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {y.y^2} \, dy$

∴ Vol = 8π

b) The line y = 2 ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy$

= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀

∴ Vol = 8/3 π

c) The y-axis ( using shell method )

h = 2-y = h = 2 - √x

p = x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

= $(2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx$

= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1 (using shell method )

p = 1 + x

h = 2√x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

Hence vol = 176/15 π

attached below is the graphical representation of P and h

3 0

3 years ago