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gulaghasi [49]
3 years ago
12

Cálculo con números racionales o fraccionarios, con raíces y potencias

Mathematics
1 answer:
gayaneshka [121]3 years ago
8 0

Answer47.5

Step-by-step explanation: add them together

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HELP ME PLEASE !!!
Mumz [18]
Instead of ∠BCA it should be ∠BAC and the value of this will be 29.
The value of ∠BOC is 58 ...this is the property of circle ...29 +29=58
5 0
4 years ago
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How many 1 x 2 shelfs cleats 8" long can be cut from a 1 x 2 board 16' long? how much is left?
inn [45]
8 i think so it might 
8 0
3 years ago
Last month, Grayson and Justine sold candy to raise money for their debate team. Justine sold 1 1/5 times as much candy as Grays
ale4655 [162]

Answer: 4/5 of a box of candy

Step-by-step explanation:

Justine sold 1¹/₅ times the ²/₃ of a box of candy that Grayson sold.

Justin sold;

= 1¹/₅ * ²/₃

= 6/5 * 2/3

= 12/15

= 4/5 of a box of candy

6 0
3 years ago
Sea un cuadrado de 2 pulgadas de lado uniendo los puntos medios se obtiene otro cuadrado inscrito en el anterior si repetimos es
Ne4ueva [31]

Answer:

1) La serie geométrica formada es

4, 2, 1,..., ∞

2) La suma al infinito de las áreas de los cuadrados es 8 in.²

Step-by-step explanation:

1) El área del primer cuadrado, a₁ = 2² = 4 pulgadas²

El área del siguiente cuadrado, a₂ = (√ (1² + 1²)) ² = (√2) ² = 2 pulg²

El área del siguiente cuadrado, a₃ = ((√ (2) / 2) ² + (√ (2) / 2) ²) = 1 pulg²

Por lo tanto, la razón común, r = a₂ / a₁ = 2/4 = a₃ / a₂ = 1/2

Las áreas de los cuadrados progresivos forman una progresión geométrica como sigue;

4, 4×(1/2), 4 ×(1/2)²,...,4×(1/2)^{\infty}

De donde obtenemos la serie geométrica formada de la siguiente manera;

4, 2, 1,..., ∞

2) La suma de 'n' términos de una progresión geométrica hasta el infinito para -1 <r <1 se da como sigue;

S_{\infty} = \dfrac{a}{1 - r}

Por lo tanto, la suma de las áreas de los cuadrados hasta el infinito se obtiene sustituyendo los valores de 'a' y 'r' en la ecuación anterior de la siguiente manera;

La \ suma \ al \ infinito \ del \ cuadrado \ S_{\infty}  = \dfrac{4 \ in.^2}{1 - \dfrac{1}{2} } = \dfrac{4 \ in.^2}{\left(\dfrac{1}{2} \right)} = 2 \times 4 \ in.^2= 8 \ in.^2

La suma al infinito de las áreas de los cuadrados, S_{\infty} = 8 in.²

7 0
3 years ago
Let f be a function of two variables that has continuous partial derivatives and consider the points a(7, 3), b(12, 3), c(7, 7),
luda_lava [24]
The directional derivative of a function f(x,y) in the direction of \mathbf v is given by

\nabla f(x,y)\cdot\mathbf v

We have \vec{ab}=\mathbf b-\mathbf a=(12-7,3-3)=(5,0), so that \|\vec{ab}\|=5, at which point we're given

\nabla f(7,3)\cdot\dfrac{(5,0)}5=5\implies1\cdot\dfrac{\partial f}{\partial x}(7,3)+0\cdot\dfrac{\partial f}{\partial y}(7,3)=5

\implies\dfrac{\partial f}{\partial x}(7,3)=5

We're also given that, in the direction of \vec{ac}=\mathbf c-\mathbf a=(7-7,7-3)=(0,4) with \|\vec{ac}\|=4, we have

\nabla f(7,3)\cdot\dfrac{(0,4)}4=4\implies0\cdot\dfrac{\partial f}{\partial x}(7,3)+1\cdot\dfrac{\partial f}{\partial y}(7,3)=4

\implies\dfrac{\partial f}{\partial y}(7,3)=4

So in the direction of \vec{ad}=\mathbf d-\mathbf a=(15-7,9-3)=(8,6), with \|\vec{ad}\|=10, we have

\nabla f(7,3)\cdot\dfrac{(8,6)}{10}=\dfrac1{10}(4,4)\cdot(8,6)=9.60
5 0
3 years ago
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