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Mekhanik [1.2K]
2 years ago
7

What is the value of C in the matrix equation below?

Mathematics
2 answers:
lara [203]2 years ago
6 0

Given:

The matrix equation is:

\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}

To find:

The value of matrix C.

Solution:

Let A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}. Then the given equation can be rewritten as

A-C=B

-C=B-A

C=-(B-A)

C=A-B

On substituting the values of the matrices, we get

C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}

C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}

C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}

C=\begin{bmatrix}-4&2&-7\end{bmatrix}

Therefore, the correct option is C.

WINSTONCH [101]2 years ago
6 0

Answer: C

Step-by-step explanation: [ 4 2 -7 ]

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