If you unroll the fence, you find it has a length equal to the circumference of a circle of radius 10 m and an average height of 3 m. Its two-sided area will be
... A = 2·(3 m)·(2π·(10 m)) = 120π m²
Then the amount of paint required is
... (120π m²) × (1L)/(100 m²) = 1.2π L ≈ 3.77 L
Answer:
y = 6x
Step-by-step explanation:
For a vertical stretch, you simply multiply x by the factor you want to stretch it by. 3x • 2 is 6x.
let's firstly convert the mixed fractions to improper fractions, and then use the LCD, which in this case is 4, to sum them up.
![\bf \stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}~\hfill \stackrel{mixed}{4\frac{3}{4}}\implies \cfrac{4\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{19}{4}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{13}{4}+\cfrac{19}{4}\implies \stackrel{\textit{using the LCD of 4}}{\cfrac{13+19}{4}}\implies \cfrac{32}{4}\implies 8](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B3%5Cfrac%7B1%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B3%5Ccdot%204%2B1%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B13%7D%7B4%7D%7D~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B4%5Cfrac%7B3%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%204%2B3%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B19%7D%7B4%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Ccfrac%7B13%7D%7B4%7D%2B%5Ccfrac%7B19%7D%7B4%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Busing%20the%20LCD%20of%204%7D%7D%7B%5Ccfrac%7B13%2B19%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B32%7D%7B4%7D%5Cimplies%208)
Answer:
3588
Step-by-step explanation:
39*92 = 3588
