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irga5000 [103]
3 years ago
12

Molly has cups of sugar. She used cup of sugar. She wants to model a subtraction problem on a number line to find how much sugar

she has left. Molly’s first step is shown below.
What should Molly do next, and how much sugar does she have left?
A. Move units to the right. She has cups of sugar left.

B. Move unit to the left. She has cup of sugar left.

C. Move units to the left. She has cup of sugar left.

D. Move unit to the right. She has cups of sugar left.

Mathematics
2 answers:
vovangra [49]3 years ago
5 0
I am going off the assumption that by "She used a cup of sugar" you mean that she used 1 cup of sugar. Since the model shows that her first step starts with 1.5, that means that she loses 1 cup, and moves 1 unit to the left. She is left with 0.5 cups of sugar.
B. She only moves 1 unit to the left.
frez [133]3 years ago
5 0

Answer:

It was 1 1/2 and 3/4 cups

Step-by-step explanation:


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For the given equation;

(3x-5)^2=-125

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}

Now that we have expanded the left side of the equation, we would have;

\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}

ANSWER:

x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3}

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