If I understand what you're saying. It would be the absolute value of -37, which is 37. Also, the absolute value of 37 is 37.
Answer:
1 3/8
Step-by-step explanation:
3 2/3 = 11/3
2 2/3 = 8/3
11/3 / 8/3 = 11/3*3/8 = 11/8 = 1 3/8
Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:

Substitute the respective values in the above formula.



Hence, the required probability is 0.55404.
Answers:
B: <em>The sine function increases on (0°, 90°) and (270°, 360°).</em>
C: <em>The cosine function decreases on (0°, 180°).</em>
E: <em>Both the cosine and sine functions have a maximum value of 1.</em>
F: <em>Both the cosine and sine functions are periodic.</em>
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