Answer:
D, two and one third
Step-by-step explanation:
i used a calculator
<u>Explanation:</u>
a) First, note that the Type I error refers to a situation where the null hypothesis is rejected when it is actually true. Hence, her null hypothesis would be H0: mean daily demand of her clothes in this region should be greater than or equal to 100.
The implication of Type I error in this case is that Mary <u>rejects</u> that the mean daily demand of her clothes in this region is greater than or equal to 100 when it is actually true.
b) While, the Type II error, in this case, is a situation where Mary accepts the null hypothesis when it is actually false. That is, Mary <u>accepts</u> that the mean daily demand of her clothes in this region is greater than or equal to 100 when it is actually false.
c) The Type I error would be important to Mary because it shows that she'll be having a greater demand (which = more sales) for her products despite erroneously thinking otherwise.
Answer:
y = -2x + 3
y = -1/2x + 5
Step-by-step explanation:
- So the best way to solve is to come up with two slopes, I'd prefer 2 perpendicular slopes because perpendicular lines only cross once hence one solution guaranteed
- so say we choose a slopeA = 2 and slopeB = -1/2, the slopes are perpendicular only if when you multiply them you get -1
- then we use the slope intercept form of an equation y = mx + b
- we make up two equations y = -2x + b and y = -1/2x + b , now we can just make up number for b so the two equations are
- y = -2x + 3
- y = -1/2x + 5
- Then we solve them by substituting for y so
- -1/2x + 5 = -2x + 3 and x = -4/3
- and then we put this to get y in either equation
- y = -2(-4/3) + 3
- y = 17/3
- So the equations work
