Answer:

mathematicallly error sentence!
<span>So rather than think about how to find the whole numbers, let's try to find the two perfect squares nearest to 38. There is one greater than it and one smaller than it. The square root will lie between the squared value of each. (e.g. 64 is the perfect square, 8 is the squared value i refer to)
</span><span>
6 ,7. 6squared is 36 and 7 squared is 42
therefore 38 lies between these two numbers</span>
Given:
The inequality is:

To find:
The domain and range of the given inequality.
Solution:
We have,

The related equation is:

This equation is defined if:


In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.
So, the domain of the given inequality is x>-3.
We know that,



The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.
So, the domain of the given inequality is y>1.
Therefore, the correct option is A.
General form of a linear equation is ax+by+c=0 where a,b, and c are three real numbers.
So, we can shift all the terms in one side of the equation. Hence, first step is to remove y from the left side. So, subtract y from each sides.
y-y=3x+2-y
0= 3x - y +2 (By simplifying)
So, the general form of the given equation is 3x-y+2=0.