Answer:
Jameson will have about $267.58 less in his account than Quincy
Step-by-step explanation:
Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.
Answer:
9c² -30c + 25
Step-by-step explanation:
Perfect square trinomial: (a - b)² = a² - 2ab + b²
(3c - 5)²
(3c)² -2(3c * 5) + 5²
9c² -2(15c) + 5²
9c² -30c + 25
Final answer: 9c² -30c + 25
Hope this helps!
There are 13 different 4 of a kinds.
4 aces 4 twos 4 threes 4 fours 4 fives 4 sixes 4 sevens 4 eights 4 nines 4 tens
1 2 3 4 5 6 7 8 9 10
4 jacks 4 queens 4 kings
11 12 13
The answer is 13 different sets.
I hope this helps :)
