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Mandarinka [93]
2 years ago
5

What is 5 to the power of 6 over 5 to the power of 2

Mathematics
2 answers:
AlekseyPX2 years ago
6 0

Answer:

625

Step-by-step explanation: 5^6/5^2

multiply 5^6 and than devide your answer with 5^2

Advocard [28]2 years ago
3 0

Answer:

625

Step-by-step explanation:

5^6=15625

5^2=25

15625/25=625

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(x+1)(6x-5) find the indefinite Integral
Elan Coil [88]

~~~~\displaystyle \int (x+1)(6x-5)~ dx\\\\\\=\displaystyle \int (6x^2-5x+6x-5)~ dx\\\\\\=\displaystyle \int(6x^2+x-5)~ dx\\\\\\=6\displaystyle \int x^2 ~ dx +\displaystyle \int  x~dx - \displaystyle \int~ 5~ dx\\\\\\=6\cdot \dfrac{x^{2+1}}{2+1} + \dfrac{x^{1+1}}{{1+1}}- 5x+C~~~~~~~~~~~~~~~~~;\left[\displaystyle \int x^n ~ dx= \dfrac{x^{n+1}}{n+1}+C,~~ n \neq -1\right]\\\\\\=6\cdot \dfrac{x^3 }{ 3} + \dfrac{x^2}2 - 5x+C\\\\\\=2x^3 +\dfrac{x^2 }{2 } - 5x +C

3 0
2 years ago
According to records from the last 50 years, there is a 2/3 chance of June temperatures being above 80 F. Azul needs to find the
dangina [55]
Here we shall use the binomial distribution formula to evaluate the probability:
let the probability that the temp will be above 80 be P(F)=2/3; 
Probability that the temp will be below 80 be P(F')=1/3
thus, 
The probability that the temp will be above 80 for 20 days for the month of June will be:
P(F)=n!/((n-x)!x!)p^xq^(n-x)
p=2/3 and q=1/3, n=30, x=20
plugging the values in the equation we obtain:
P(F)=30!/(10!*20!)*(2/3)^20*(1/3)^(30-20)
P(F)=0.153



6 0
3 years ago
Read 2 more answers
QUOTIENT OF 84 AND 6
iris [78.8K]

Answer:

Yo, 84/6 is 14

Step-by-step explanation:

The quotient is the answer you get from a division problem.

8 0
3 years ago
Read 2 more answers
A ship travels due north for 100 miles from point C to point A. From point A the ship travels to point B at 60° east of north. F
Karo-lina-s [1.5K]

Answer:

AandB=80miles

Total=240miles

Step-by-step explanation:

Draw the figure first indicating the figures then find the distance each degrees then find the total

4 0
3 years ago
Find the amount in a continuously compounded account for the following condition. ​Principal, ​$​4000; Annual interest​ rate, 5.
soldi70 [24.7K]
<h3>Answer:  4745.96 dollars</h3>

=======================================================

Explanation:

We have this given info

  • P = 4000 = principal
  • r = 0.057 = annual interest rate in decimal form
  • t = 3 = number of years

Use this to plug into the formula below

A = Pe^{r*t}\\\\A = 4000*e^{0.057*3}\\\\A \approx 4,745.96299608713\\\\A \approx 4,745.96\\\\

You'll need your calculator, and the calculator needs the "e" button.

The "e" refers to the special constant 2.718... which is similar to pi = 3.14...

7 0
2 years ago
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