2x+4≤3(x+2) Multiply numbers 8≤3(x+2) distribute 3 through the parenthesis 8 ≤ 3x +6 Move the variable to the left and change ints sign 8 - 3x ≤ 6 Move the constant to the right-hand side And change its sign -3x ≤ 6 - 8 Calculate the diffrences -3x ≤ -2 Divide both sides of the inequiality by -3 and flip the inequality sign X ≥ 2/3 - solution
The sum in sigma notation for the sequence will be as follows: From <span>5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 + 50 first term=5 common difference=5 number of terms=10 n=nth term thus the sum will be: (i=2 to 10)</span>∑(5(n-1)+5)
