Question

Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for several seconds. The player began counting at 000 seconds, even though the video had already played 190190190 frames. The video plays 252525 frames per second. How many frames had the video already played when the time was equal to -3\dfrac{2}{5}−3 5 2 ​ minus, 3, start fraction, 2, divided by, 5, end fraction seconds?

Answer 1

Answer:

105 frames

Step-by-step explanation:

Given that:

At 0 seconds, the video had already played 190 frames and there are 25 frames being played per second.

When the time is equal to $3 \dfrac{2}{5}$, the number of frames that are already being played is:

$= 3 \dfrac{2}{5} \times 25$

$= \dfrac{17}{5} \times 25$

= 17 × 5

= 85 frames.

But recall that, the frames had already played 190 frames at 0 seconds, then the number of frames that had already been played when the time is equal to $3 \dfrac{2}{5}$ is;

=(190 - 85) frames

= 105 frames

Answer 2

Answer:

105

Step-by-step explanation:

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