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denpristay [2]
3 years ago
5

Help anyone?!!! I need helppp

Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0

I looked at the other one you just asked and I couldn't figure it out.  I understand this one.

Laney goes from 1 to 5, Gus from 1 to 6, Gus has the greater range.  TRUE

Just eyeballing the data, Gus's median is 5, Laney's is 3.  TRUE

Laney's data is more symmetrical, closer to the usual bell shape.  Gus is heavily weighted toward the higher values, less symmetrical. TRUE

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In the diagram below, the angle of depression from the top of the lighthouse to a speed boat is 27 degrees.  The base of the lig
elixir [45]

Answer:

=

412

feet

Step-by-step explanation:

The angle of depression is always measured from the horizontal.

A triangle is formed by the lighthouse, the ground and the boat. The angle of depression is not in the triangle, but it is equal to the angle of elevation at the boat. (Alternate angles on parallel lines)

The angle at the top of the lighthouse, inside the triangle is:

90°−27°

=63°

The distance to the boat is the side opposite the angle of

63°

while the height of the lighthouse is the adjacent side.

opposite

adjacent

=tan 63°

distance

210=tan 63°

distance=210×tan 63°=412 feet

7 0
2 years ago
Read 2 more answers
Bicycles have 2 wheels an tricycles have 3. There are a total of 7 bicycles and tricycle. If there are 17 wheels in all how many
Anika [276]
There are 7 bicycles and 1 tricycle
5 0
2 years ago
According to a study conducted by the Gallup Organization, the the proportion of Americans who are afraid to fly is 0.10. A rand
notsponge [240]

Answer: 0.1457

Step-by-step explanation:

Let p be the population proportion.

Given: The proportion of Americans who are afraid to fly is 0.10.

i.e. p= 0.10

Sample size : n= 1100

Sample proportion of Americans who are afraid to fly =\hat{p}=\dfrac{121}{1100}=0.11

We assume that the population is normally distributed

Now, the probability that the sample proportion is more than 0.11:

P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]

Hence, the probability that the sample proportion is more than 0.11 = 0.1457

3 0
3 years ago
A football game lasted 3.15 hours. how many seconds did the game last? if necessary, round your answer to the nearest tenth of a
Eva8 [605]
It would be 11340 seconds. 
Hope this helps!
6 0
3 years ago
Read 2 more answers
Help please :&lt;<br> I don't get this that well
Thepotemich [5.8K]

Answer:

1. Combining like terms

2. Distributive property

3. Subtraction (both sides)

4. Addition(both sides)

5. Division

Step-by-step explanation:

7 0
3 years ago
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