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hodyreva [135]
2 years ago
13

What is the polynomial function of lowest degree with rational real coefficients, and roots -3 and square root of 6?

Mathematics
1 answer:
telo118 [61]2 years ago
4 0

9514 1404 393

Answer:

  f(x) = x³ +3x² -6x -18

Step-by-step explanation:

In order for there to be a root of √6, there must be a factor of (x-√6). In order for there to be rational coefficients, there needs to be another factor of (x+√6) in the minimal polynomial. Then the minimal polynomial with the required roots is ...

  f(x) = (x +3)(x -√6)(x +√6) = (x +3)(x² -6)

  f(x) = x³ +3x² -6x -18

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The area of a parallelogram is 96 cm squared the height is 4 cm less than the length what is
andrey2020 [161]
Area of paralellogram=legnth times height

l=legnth
h=height
area=96

lh=96

h is 4 less than l
h=-4+l
sub
l(-4+l)=96
-4l+l^2=96
minus 96 both sides
l^2-4l-96=0
factor
(l-12)(x+8)=0
set to zero
l-12=0
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l=-8, imossible, legnth cannot be negative, disreagard this soultion

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Answer:

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