Answer:
11:35 AM
Step-by-step explanation:
Lets start with the hours:
9+2=11
Now the minutes:
15+20=35
Now put them together:
11:35 AM
#2
2x - 4y = -2
2x + 3y = -16
------------------subtract
-7y = 14
y = 14/-7
y = -2
2x - 4y = -2
2x - 4(-2) = -2
2x + 8 = -2
2x = -2 -8
2x = -10
x = -10/2
x = -5
answer x = -2 and y = -5
check:
2(-5)- 4(-2) = -2
-10 +8 = -2
-2 = -2.....true
2x + 3y = -16
2(-5)+3(-2) = -16
-10 + (-6) = -16
-16 = -16...true
Answer:
Step-by-step explanation: No, Gavin is not correct because 284.42 is less than 400 the equation is 200(1+0.09/2)^8 when solved you get 284.42 which is not enough.
Step-by-step explanation:
simplifying this
Ok so do 0.09/2 which is 0.045 then add 1 so you get 200•1.045^8 then you do 1.045^8= 1.422100.... so I did 1.422100•200 to get the final answer of 284.42
So given the values on the number line, AB and BC, adding them together will get the length of AC. If AB equals

and BC equals

, the value of AC should be

. Since you are given the length of AC,

, you can create an equation to solve for x. This equation would be

. Isolating the x on the left (or right hand side) gets the value of x to be 19. The same thing goes for the 2nd question.
Answer:
98 is the answer of the expression
Step-by-step explanation:
AS it is a simple algebraic expression so these are solved by BDMAS rule which means that we have to solve the brackets first starting from the smaller bracket first which is inside a larger bracket then we will move to Division then multiplication then addition and then subtraction
so the following equation can be written as
= ![2^{3}[\frac{1}{4}+4(36/12)]](https://tex.z-dn.net/?f=2%5E%7B3%7D%5B%5Cfrac%7B1%7D%7B4%7D%2B4%2836%2F12%29%5D)
First of all solving smallest bracket and division inside it
= ![2^{3}[\frac{1}{4}+4(3)]](https://tex.z-dn.net/?f=2%5E%7B3%7D%5B%5Cfrac%7B1%7D%7B4%7D%2B4%283%29%5D)
Multplying 4 inside
= ![2^{3}[\frac{1}{4}+12]](https://tex.z-dn.net/?f=2%5E%7B3%7D%5B%5Cfrac%7B1%7D%7B4%7D%2B12%5D)
Now solving the 2³
= ![8[\frac{1}{4}+12]](https://tex.z-dn.net/?f=8%5B%5Cfrac%7B1%7D%7B4%7D%2B12%5D)
Now solving the expression inside the bracket by taking LCM
= ![8[\frac{1 + 4*12}{4}]](https://tex.z-dn.net/?f=8%5B%5Cfrac%7B1%20%2B%204%2A12%7D%7B4%7D%5D)
= ![8[\frac{1 + 48}{4}]](https://tex.z-dn.net/?f=8%5B%5Cfrac%7B1%20%2B%2048%7D%7B4%7D%5D)
= ![8[\frac{49}{4}]](https://tex.z-dn.net/?f=8%5B%5Cfrac%7B49%7D%7B4%7D%5D)
Now multiplying 8 with inside values
= ![[\frac{8*49}{4}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B8%2A49%7D%7B4%7D%5D)
AS 8 cuts out with 4 so
= 2 * 49
= 98
which is the answer of the expression