I need help anyone??? please??????

Mathematics

2 answers:

olchik [2.2K]3 years ago

8 0

The principal square root of 49 is just 7 because 7 times 7 is 49.
It can not be -7 because a principle square root cannot be negative.

$\sf\ Answer: A)\ 7$

$\sf\ \sqrt{49}=\\\±7\\\\-7\ and\ 7\ are\ both\ square\ roots\ of\ 49\ because\ 7\times7=49\ and\\\\-7\times-7=49.\\\\But\ as\ I\ said\ before,\ principal\ square\ roots\ can\ not\ be\ negative\\\\numbers.\\\\That\ will\ eliminate\ any\ options\ with\ -7.\\\\So\ the\ only\ principal\ square\ root\ that\ we\ have\ is\ {\boxed{7}$

Ronch [10]3 years ago

5 0

The answer would be 7
because the square root of 49 is 7.
so 7 multiplied 7 is ..49

The answer wont be -7 because in Principal root,
negative numbers are not involved, you cant do it! :)

That being said you'd also be able to know that since no negative numbers are allowed in principle root, -7 and 7 are out as choices, and D is totally wrong since we now know what the priniciple root means :)
The answer is 7
Hope this helped !

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3 years ago

Find all the whole values of a for which the solution of the equation ax = 6 is a whole number.

Marianna [84]

Answer:

Step-by-step explanation:

The given equation is,

$\Rightarrow ax = 6$

$\Rightarrow x = \dfrac{6}{a}$

We need to to find all the whole values of a for which the solution of the equation i.e x will be a whole number.

We know that when a number is divided by one of its factor it leaves a remainder of 0 or the result we get is a whole number.

That is why, we need a as one of the factors of 6, i.e 1, 2, 3, 6 in order to get x as a whole number.

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3 years ago

Simplify the expression (x^3- 5x^2 + 7x - 12) ÷ (x – 4) using long division

Kisachek [45]

Answer:

${x}^{2} - x + 3$

Step-by-step explanation:

Instead, since the divisor is in the form of $x - c$ , use what is called Synthetic Division. Remember, in this formula, $-c$ gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

4| 1 −5 7 −12

↓ 4 −4 12

_______________

1 −1 3 0 → ${x}^{2} - x + 3$

You start by placing the $c$ in the top left corner, then list all the coefficients of your dividend [x³ - 5x² + 7x - 12]. You bring down the original term closest to $c$ then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an ${x}^{2}$ , the −1 [ $x$ ] follows right behind it, and bringing up the rear, comes the 3, giving you the quotient of ${x}^{2} - x + 3$ .