Answer:
a) The mean of the data set is 58.3.
b) The standard deviation of the data-set is of 10.8.
c) 50% of presidents' ages fall within one standard deviation of the mean
Step-by-step explanation:
Question a:
Sum of all values divided by the number of values.

The mean of the data set is 58.3.
Question b:
Square root of the sum of the difference squared between each value and the mean, divided by the number of values subtracted by 1. So

The standard deviation of the data-set is of 10.8.
Question c:
Between 58.3 - 10.8 = 47.5 and 58.3 + 10.8 = 69.1.
3 out of 6(Reagan, Bush and W. Bush), so:
3*100%/6 = 50%
50% of presidents' ages fall within one standard deviation of the mean