Answer:
a= 7.5%12.58= 0.9435 round 0.94+12.58= 13.52
b= 31.50 divided by 19.00= 1.65789474 round 1.66
c= (14.25 x 18)+ (5.5%250)
l l
v v
256.50 + 13.75 = 270.25
Step-by-step explanation:
Answer:
Step-by-step explanation:
A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting 30 values and obtaining an average greater than 3.6.
We can denote the population mean with the symbol 
According to the information given, the data have a population mean:
.
The standard deviation of the data is:
.
Then, from the data, a sample of size 
is taken.
We want to obtain the probability that the sample mean is greater than 3.6
If we call
to the sample mean then, we seek to find:
To find this probability we find the Z statistic.
Where:
Where 
is the standard deviation of the sample
Then:
The probability sought is: 
When looking in the standard normal probability tables for right tail we obtain:
Step-by-step explanation:
5-(x-2)²
When x=-1, then
- 5-(-1-3)²
- 5-(-4)²
- 5-(-4×-4)
- 5-16
- -11
Answer: the answer should be 73.6 so hopefully that is the correct answer.
Step-by-step explanation: to find the answer you multiply 1/2 times 4 times 4 times 9.2 making the results to be 73.6 so hopefully that is the correct answer and mark me brainliest please.
Answer:
x = 30
m<Y = 60
m<Z = 60
m<X = 60
Step-by-step explanation:
All of this should add up to 180 so...
2x + 2x + 3x - 30 = 180 (collect like terms)
7x - 30 = 180 (add 30 on both sides)
7x = 210 (divide by 7 on both sides)
x = 30
PLUG IN
2(30) = 60
3(30) - 30
90 - 30 = 60
m<Y = 60
m<Z = 60
m<X = 60
equilateral triangle
Hope this helps ya! Keep smiling!
