Let:
Vbu= Volume of the buret
Vbk= Volume of the beaker
A buret initially contains 70.00 millimeters of a solution and a beaker initially contains 20.00 ml of the solution the buret drips solution into the Beaker. each drip contains 0.05 mL of solution, therefore:
x = Number of drips
a = volume of each drip
after how many drips will the volume of the solution in the buret and beaker be equal ? Vbu = Vbk:
both (0,350) and (250,700) fall in the shaded are
and check:
350 *3 = 1050, which is more than 1000 and more than double the amount of hotdogs ( 0)
700 *3 = 2100, so over 1000 and more than double the amount of hotdogs(250*2=500)
so those 2 are correct
Answer:
312π mm³
Step-by-step explanation:
Given:
Oblique cone height, h = 14 mm
radius of half sphere = base radius of cone, r = 6 mm
Recall the volume of 1/2 - sphere
= 1/2 x volume of sphere
= 1/2 x (4π/3) r³
= 1/2 x (4π/3) (6)³
= 144π
Also volume of an oblique cone =
=volume of a right cone
= (π/3) r²h
= (π/3) 6²(14)
=168π
Volume of composite figure = 144π + 168π = 312π mm³
Answer:
19.5
Step-by-step explanation:
78 divided by 4
Answer:
150
Step-by-step explanation:
300-150
