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allochka39001 [22]
3 years ago
8

SOLVE EQUATION solve for x |3x+19|=13

Mathematics
2 answers:
ivanzaharov [21]3 years ago
3 0

Answer:

answer is 20............

Step-by-step explanation:

3x=13-19

x= -6/3

x= -2

kaheart [24]3 years ago
3 0

Answer:

= -2

Step-by-step explanation:

3x+19=13

3x=13-19

3x/3= 6/3

X= -2

Answer from Gauthmath

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A cylinder has volume 78 cm³. What is the volume of a cone with the same radius and height?​
OleMash [197]

Answer:

The volume of the cone is 26\ cm^{3}

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2}h

In this problem we have that

V=78\ cm^{3}

so

78=\pi r^{2}h -----> equation A

The volume of a cone with the same radius and height is equal to

V=\frac{1}{3}(\pi r^{2}h) -----> equation B

Substitute equation A in equation B

V=\frac{1}{3}(78)

V=26\ cm^{3}

6 0
4 years ago
Identify the graph of the solution set of -2.3< 4 + 0.9y
aleksandrvk [35]
The answer is A assuming that the 7 is negative cause its on the left side of the 0 but I am positive the answer is A
8 0
3 years ago
What is the formula of simple interest?​
Annette [7]

Answer:

simple interest = principle*rate*time

5 0
4 years ago
Read 2 more answers
Please answer this question!
bonufazy [111]

Answer:

X = 9 or 1/3

Step-by-step explanation:

Explanation given in attachment in order to well articulate the logarithm sign.

Note addition in logarithm means multiplication.

The logarithm of a number the same as the base is 1.

6 0
4 years ago
Line v passes through point [6.6] and is perpendicular to the graph of y= 3/4x - 11 line w is parallel to line v and passes thro
lbvjy [14]

Given:

The equation of a line is

y=\dfrac{3}{4}x-11

Line v passes through point (6,6) and it is perpendicular to the given line.

Line w passes through point (-6,10) and it is parallel to the line v.

To find:

The equation in slope intercept form of line w.

Solution:

Slope intercept form of a line is

y=mx+b         ...(i)

where, m is slope and b is y-intercept.

We have,

y=\dfrac{3}{4}x-11      ...(ii)

On comparing (i) and (ii), we get

m=\dfrac{3}{4}

So, slope of given line is \dfrac{3}{4}.

Product of slopes of two perpendicular lines is -1.

m_1\times m_2=-1

\dfrac{3}{4}\times m_2=-1

m_2=-\dfrac{4}{3}

Line w is perpendicular to the given line. So, the slope of line w is -\dfrac{4}{3}.

Slopes of parallel line are equal.

Line v is parallel to line w. So, slope of line v is also -\dfrac{4}{3}.

Slope of line v is -\dfrac{4}{3} and it passes thorugh (-6,10). So, the equation of line v is

y-y_1=m(x-x_1)

where, m is slope.

y-10=-\dfrac{4}{3}(x-(-6))

y-10=-\dfrac{4}{3}(x+6)

y-10=-\dfrac{4}{3}x-\dfrac{4}{3}(6)

y-10=-\dfrac{4}{3}x-8

Adding 10 on both sides, we get

y=-\dfrac{4}{3}x-8+10

y=-\dfrac{4}{3}x+2

Therefore the equation of line v is y=-\dfrac{4}{3}x+2.

3 0
3 years ago
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