Answer:
-2.2, -1 7/10, 1.7, 3 1/4
X^3 - 14x^2 + 49x = 0
Factor an x out:
x(x^2 - 14x + 49) = 0
Find two factors of 49 that add to -14 (-7 and -7). Convert the trinomial to two binomials:
x(x - 7)(x - 7) = 0
The zeros are:
x = 0 and x = 7.
7 occurs as a zero twice and therefore has a multiplicity of 2.
From what I remember it is -x-31y
Answer:
23
Step-by-step explanation:
By definition of dot-product
sum the corresponding products.
u * v = <9, 4> *<3, -1> = 9*3 + 4*(-1) = 27 -4 = 23