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muminat
3 years ago
14

A restaurant placed a 2- quarter pitcher of water on each 76 tables. the water was severed from from a 50- gallon containter. Ho

w many QUARTS of water remained in the 50- gallon container after all ther pitchers were filled
(4 quarts=1 gallon)
Mathematics
2 answers:
allochka39001 [22]3 years ago
5 0
Answer is 24

Step by step.

(50x2)-76
Law Incorporation [45]3 years ago
4 0

Answer:

There would be 12 gallons left

Step-by-step explanation:

If there was 76 of the 2 quarter pitchers that would make 152 Qt and 152 Qt equals 38 gallons so 50 - 38 = 12

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Given the function f(x) = 3 (x - 9) + 6 which of the following represents f-1 (x)?
igomit [66]

Answer:

f^{-1}(x) = \frac{1}{3} x + 7

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 3(x - 9) + 6 ← distribute and simplify right side

y = 3x - 27 + 6 = 3x - 21 ( add 21 to both sides )

y + 21 = 3x ( divide all terms by 3 )

\frac{1}{3} y + 7 = x

Change y back into terms of x with x = f^{-1}(x) , thus

f^{-1}(x) = \frac{1}{3} x + 7

5 0
3 years ago
The number of boys and girls in a class are in the ratio 5:4. If the
vichka [17]

Answer:

no.of boys is 45

Step-by-step explanation:

here, let the number of boys and girls be 5x and4x

ATQ,

5x=4x+9

or,5x-4x=9

or,x=9

then, the number of boys is 9×5=45

and the number of girls is 9×4=36..

3 0
3 years ago
The original selling price was ​$154.30 The sale price was ​$127.92 What is the first step in finding the percent​ markdown?
Annette [7]

Answer:

subtract the new price from the original price

Step-by-step explanation:

To find the percent markdown, first subtract the new price from the original price

154.30-127.92

26.38

Then divide by the original price

26.38/154.30

.170965651

Multiply by 100% to get the percent decrease

17.0965651% decrease

7 0
2 years ago
Quadratic formula 3x^2 - 2x + 5 = 0
Tanzania [10]

Step-by-step explanation:

The given quadratic equation is :

3x^2 - 2x + 5 = 0

We need to solve the given equation. The formula used to solve a quadratic equation is :

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

We have, a = 3, b = -2 and c = 5

So,

x=\dfrac{-(-2)\pm \sqrt{(-2)^2-4(3)(5)}}{2(3)}\\\\x=0.333,4.667

Hence, this is the required solution.

4 0
3 years ago
Solve for x x/7 +9=15
Ymorist [56]
Subtract the 9 from 9 to cancel it out. Then subtract 9 from 15, which is 6. And 6 times 7 is 42.

6 0
3 years ago
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