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Mila [183]
3 years ago
7

Solve the equation for x 3x + 20 = x - 8

Mathematics
2 answers:
lesantik [10]3 years ago
4 0

Answer:

x=−14

Step-by-step explanation:

Step 1: Subtract x from both sides.

3x+20−x=x−8−x

2x+20=−8

Step 2: Subtract 20 from both sides.

2x+20−20=−8−20

2x=−28

Step 3: Divide both sides by 2.

2x

2

=

−28

2

x=−14

spin [16.1K]3 years ago
4 0

Answer:

x = 9.33333333333

Step-by-step explanation:

How to solve...

3x + 20 = x - 8

     +   8 = x + 8

----------------------  ( add 8 on both sides )

  <u>3x + 28 = x</u>

 3x  + 28 = 3x

---------------------- ( divide 3x on both sides )

     <u>28 = 3x</u>

      3  =  x

---------------------- ( divide 28 by 3 )

x = 9.33333333333

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A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
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Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

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P(YX) =0.6 \times 0.01

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The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

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(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

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3 years ago
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