Help pls 10-11 plsssssss
2 answers:
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Answer:
C(t) = I/F [1 - e^(-Ft/V) ] + C₀e^(-Ft/V)
as t = 0 ; C(t) = 1/F
Explanation:
dC/dt) = (-F/V)*C+(I/V)
To make it easier to solve, let
Constants: I, V,F
Variables: C, t
workings and solution can be viewed below
Let's plug the value:
Recall that exponent and logarithm are inverse operations:
So, we have
If for the slower printer it takes 10 hours for the whole thing, how much has it done in 1 hour? well, since it takes 10 hours total, in 1 hour it has only done 1/10 th of the whole work.
the faster printer however, can do it in 6 total, how much has it done in 1 hour? well, 1/6 of the whole work.
now, let's say, they both work together, and it takes "t" hours to finish the whole thing with both rolling.
let's add both rates to see how much that is,
which is 3 hours and 45 minutes.
the faster printer however, can do it in 6 total, how much has it done in 1 hour? well, 1/6 of the whole work.
now, let's say, they both work together, and it takes "t" hours to finish the whole thing with both rolling.
let's add both rates to see how much that is,
which is 3 hours and 45 minutes.