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ankoles [38]
3 years ago
6

TIME REMAINING

Mathematics
2 answers:
Ratling [72]3 years ago
6 0

Answer:

  • A. w = (-7/2)z <em>or </em>w equals negative StartFraction 7 Over 2 EndFraction z

Step-by-step explanation:

  • 5w + 9z = 2z + 3w
  • 5w - 3w = 2z - 9z
  • 2w = - 7z
  • w = (-7/2)z

Correct choice is A

Leya [2.2K]3 years ago
3 0

Answer:

w=-7/2z

Step-by-step explanation:

to solve for w you firstly have to group the like terms

5w-3w=2z-9z

2w=-7z

then you have to divide both sides by 2 inorder to remain with w on one side.

2w/2=-7/2

w=-7/2

I hope this helps

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When rolling a die, what is the probability of rolling a 1 or a 4 write your answer in a fraction?
Andrej [43]

Answer:

1/3

Step-by-step explanation:

There are 6 values on a die, and we want 2 values. The fraction now is 2/6. But, wait! We can simplify this fraction: 1/3.

Side note:

I understand if you wanted just the 2/6 fraction and not simplified.

3 0
3 years ago
Instructions:Select the correct answer from each drop-down menu. ∆ABC has vertices at A(11, 6), B(5, 6), and C(5, 17). ∆XYZ has
Akimi4 [234]

to compare the triangles, first we will determine the distances of each side

<span>Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
</span>Solving 

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

<span>AB = 6 units   BC = 11 units AC = 12.53 units
</span><span>∆XYZ  X(-10, 5), Y(-12, -2), and Z(-4, 15)
</span><span>XY = 7.14 units   YZ = 18.79 units XZ = 11.66 units</span>

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>MN = 6 units   NO = 11 units MO = 12.53 units
</span><span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).
</span><span>JK = 5 units   KL = 9 units JL = 10.30 units
</span><span>∆PQR  P(12, 3), Q(12, -2), and R(3, -2)
</span><span>PQ = 5 units   QR = 9 units PR = 10.30 units</span> 
Therefore
<span>we have the <span>∆ABC   and the </span><span>∆MNO  </span><span> 
with all three sides equal</span> ---------> are congruent  
</span><span>we have the <span>∆JKL  </span>and the <span>∆PQR 
</span>with all three sides equal ---------> are congruent  </span>

 let's check

 Two plane figures are congruent if and only if one can be obtained from the other by a sequence of rigid motions (that is, by a sequence of reflections, translations, and/or rotations).

 1)     If ∆MNO   ---- by a sequence of reflections and translation --- It can be obtained ------->∆ABC 

<span> then </span>∆MNO<span> ≅</span> <span>∆ABC  </span> 

 a)      Reflexion (x axis)

The coordinate notation for the Reflexion is (x,y)---- >(x,-y)

<span>∆MNO  M(-9, -4), N(-3, -4), and O(-3, -15).</span>

<span>M(-9, -4)----------------->  M1(-9,4)</span>

N(-3, -4)------------------ > N1(-3,4)

O(-3,-15)----------------- > O1(-3,15)

 b)      Reflexion (y axis)

The coordinate notation for the Reflexion is (x,y)---- >(-x,y)

<span>∆M1N1O1  M1(-9, 4), N1(-3, 4), and O1(-3, 15).</span>

<span>M1(-9, -4)----------------->  M2(9,4)</span>

N1(-3, -4)------------------ > N2(3,4)

O1(-3,-15)----------------- > O2(3,15)

 c)   Translation

The coordinate notation for the Translation is (x,y)---- >(x+2,y+2)

<span>∆M2N2O2  M2(9,4), N2(3,4), and O2(3, 15).</span>

<span>M2(9, 4)----------------->  M3(11,6)=A</span>

N2(3,4)------------------ > N3(5,6)=B

O2(3,15)----------------- > O3(5,17)=C

<span>∆ABC  A(11, 6), B(5, 6), and C(5, 17)</span>

 ∆MNO  reflection------- >  ∆M1N1O1  reflection---- > ∆M2N2O2  translation -- --> ∆M3N3O3 

 The ∆M3N3O3=∆ABC 

<span>Therefore ∆MNO ≅ <span>∆ABC   - > </span>check list</span>

 2)     If ∆JKL  -- by a sequence of rotation and translation--- It can be obtained ----->∆PQR 

<span> then </span>∆JKL ≅ <span>∆PQR  </span> 

 d)     Rotation 90 degree anticlockwise

The coordinate notation for the Rotation is (x,y)---- >(-y, x)

<span>∆JKL  J(17, -2), K(12, -2), and L(12, 7).</span>

<span>J(17, -2)----------------->  J1(2,17)</span>

K(12, -2)------------------ > K1(2,12)

L(12,7)----------------- > L1(-7,12)

 e)      translation

The coordinate notation for the translation is (x,y)---- >(x+10,y-14)

<span>∆J1K1L1  J1(2, 17), K1(2, 12), and L1(-7, 12).</span>

<span>J1(2, 17)----------------->  J2(12,3)=P</span>

K1(2, 12)------------------ > K2(12,-2)=Q

L1(-7, 12)----------------- > L2(3,-2)=R

 ∆PQR  P(12, 3), Q(12, -2), and R(3, -2)

 ∆JKL  rotation------- >  ∆J1K1L1  translation -- --> ∆J2K2L2=∆PQR 

<span>Therefore ∆JKL ≅ <span>∆PQR   - > </span><span>check list</span></span>
6 0
3 years ago
What is the total cost of $ 2.95 notebook plus 5 %
nordsb [41]
First, you convert 5% to decimal. For your info, percents are always equal to 100. So, you divide 5 by a 100, which gives you 0.05. Then, you multiply 2.95 by 0.05. 2.95 x 0.05 is 0.1475 which is about 0.15. Then, you add 0.15 to 2.95. The total cost of a $2.95 notebook plus 5% is about $3.10.

5 0
3 years ago
F(1) = 55, f(n)=f(n - 1) +8; 95<br> The term 95 is the _th term<br><br> Need help quickly
Viefleur [7K]

Answer:

6th term

Step-by-step explanation:

95=55+8n-8

95-55=8n-8

40+8=8n

48/8=8n/8

6=n

5 0
2 years ago
What is the approximate curcumfrance of the circle shown below?​
Vikki [24]

Answer:

C.

Step-by-step explanation:

Circumference=PI*diameter

Circumference=3.14*19.5

Circumference=61.23 rounds to 61.2 so the answer is C

3 0
3 years ago
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