3 years ago

16-3p=2/3p+5? can you plz help me

Mathematics

1 answer:

Crank3 years ago

5 0

<span>16-3*p-(2/3*p+5)=0
</span>Hope this helped :)

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Answer:

The answer is (5, 2)

Step-by-step explanation:

I. If move left = -x

move right = +x

So -2 - 3 = -5 => move left

-5 + 10 = 5 => move right

I suggest that move left and right is x cordinate

The answer is (5,2)

Is that correct?

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2 years ago

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Step-by-step explanation:

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3 years ago

Find the 5th term of the expansion of ( 6x + 6y)^11

Elodia [21]

The 5 th term of the given expression is 330 $(6x)^{7}( 6y)^{4}$ .

Step-by-step explanation:

Given,

$(6x+6y)^{11}$

To find the 5th term of the given expression.

Formula

In a binomial series $(a+b)^{n}$ , the r th term is = nC(r-1) $a^{n-r-1} b^{r-1}$ , where,

nC(r-1) = $\frac{n!}{(r-1)!(n-r+1)!}$

Now,

Putting, n=11, r = r, a=6x and b=6y we get,

5 th term = 11C4 $(6x)^{7}( 6y)^{4}$

= $\frac{11!}{4!7!}$ $(6x)^{7}( 6y)^{4}$

= $\frac{11X10X9X8X7!}{7!X4X3X2X1}$ $(6x)^{7}( 6y)^{4}$

= 330 $(6x)^{7}( 6y)^{4}$

Here is the answer.

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3 years ago