A block of aluminum occupies a volume of 15.0 ml and weighs 40.5 g. What is it's density?
1 answer:
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Answer is : 8v^3+ 14v^2+11v+3
For cubic feet
Solution
Formula : volume base area x height
So base area = 4v^2 +5v+3
Height = 2v+1
So multiply
Volume =(4v^2+5v+3) x(2v+ 1)
The rest is below
For cubic feet
Solution
Formula : volume base area x height
So base area = 4v^2 +5v+3
Height = 2v+1
So multiply
Volume =(4v^2+5v+3) x(2v+ 1)
The rest is below