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lora16 [44]
3 years ago
5

Want to help me thanks if not ok to will give brainliest

Mathematics
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

The answer is 18.2

Step-by-step explanation:

17+24+19+17+14=91

91/5=18.2

You might be interested in
How do I multiply polynomials
balu736 [363]

Answer:

  Multiply each term of one by every term of the other.

Step-by-step explanation:

The distributive property can help you keep it all straight.

  (a +b +c)(d +e) = a(d +e) +b(d +e) +c(d +e)

  = ad +ae +bd +be +cd +ce

The above shows how each term of one sum is multiplied by every term of the other.

When doing this with polynomials, the rules of arithmetic and exponents apply, so the power of the variable in each product will be the sum of the powers of that variable in each of the terms being multiplied.

<u>Example</u>

(x^2 +x)(x^3 +5) = x^2(x^3 +5) +x(x^3 +5)

  = x^5 +5x^2 +x^4 +5x

We have chosen an example that has every product with a different power of x. If there were like terms, they would be combined in the usual way.

_____

With some practice, there are methods available for multiplying longer polynomials without the tedium of writing down lots of intermediate terms. The basic idea is to use mental arithmetic to sum the products that will make up a particular term of the result.

<u>Example</u>

  (x^2 +2x +3)(5x^2 +7x +11)

You know this product will have terms ranging from x^4 down to a constant. The x^4 term is the product of the leading terms: (x^2)(5x^2) = 5x^4.

The x^3 term is the sum of products of x^2 and x terms: (x^2)(7x) +(2x)(5x^2) = 17x^3.

The x^2 term is the sum of products of x^2 and constant terms, along with the product of x terms: (x^2)(11) +(2x)(7x) +(3)(5x^2) = 40x^2.

The x-term and constant-term are found in similar fashion. Enough has been shown to give you the flavor of the method.

Perhaps you can see that this understanding will let you write the product of the polynomials very quickly.

_____

Multiplying polynomials is somewhat like multiplying decimal numbers. In multiplying numbers, you separate the product into different powers of 10, but in multiplying polynomials, you keep the products together that apply to the different powers of x.

(12)(35) = (10)(30) +(10)(5) +(2)(30) +(2)(5) = 300 +50 +60 +10 = 420

(x+2)(3x+5) = (x)(3x) +(x)(5) +(2)(3x) +(2)(5) = 3x^2 +11x +10

  If x=10, then 3x^2 +11x +10 = 300 +110 +10 = 420, matching the numerical version.

5 0
4 years ago
Expand and simplify <br> (X+7)(x-9)
Lorico [155]

Answer:

X²+16x-63

Step-by-step explanation:

expand out the brackets to get:

X²+9x+7x-63

simplify:

X²+16x-63

5 0
3 years ago
Give the inequality -8&lt;2 explain what happens when you multiply or divide both sides by 2 and what happens when you multiply
rodikova [14]

Answer:

If we multiply both the sides by 2, the inequality signs remains the same.

If we divide both sides by -2, the sign changes.

Step-by-step explanation:

The given inequality is

-8<2

If we multiply both the sides by 2, we get

-8 * 2 < 2*2

-16 < 4

The inequality signs remains the same.

On the other hand if we divide both sides by -2, we get -

-8/-2 < 2/-2

4 > -1

Here the sign changes.

4 0
3 years ago
Linda received the following scores on her essay tests.
lord [1]
First, we add the numbers. This gives us 715.
Then, we divide it by the amount of numbers. This gives us. 715 divided by 11.

This simplifies to 65.
4 0
3 years ago
Read 2 more answers
) How many degrees of freedom are available for hypothesis tests and confidence intervals for single regression coefficient
sladkih [1.3K]

Answer:

We use students' t distribution therefore degrees of freedom is v= n-2

Step-by-step explanation:

<u>Confidence Interval Estimate of Population Regression Co efficient β.</u>

To construct the confidence interval for β, the population regression co efficient , we use b, the sample estimate of β. The sampling distribution of b is normally distributed with mean β and a standard deviation σ.y.x / √(x-x`)². That is the variable z = b - β/σ.y.x / √(x-x`)² is a standard normal variable. But σ.y.x  is not known so we use S.y.x and also student's t distribution rather than normal distribution.

t= b - β/S.y.x / √(x-x`)² = b - β/Sb    [Sb = S.y.x / √(x-x`)²]

with v= n-2 degrees of freedom.

Consequently

P [ - t α/2<  b - β/Sb  < t α/2] = 1- α

or

P [ b- t α/2 Sb<   β  < b+ t α/2 Sb] = 1- α

Hence a 100( 1-α) percent confidence for β the population regression coefficient for a particular sample size n <30  is given by

b± t α/2 Sb

Using the same statistic a confidence interval for α can be constructed in the same way for  β  replacing  a with b and Sa with Sb.

a± t α/2 Sa

Using the t statistic  we may construct the confidence interval for U.y.x for the given value X0 in the same manner

Y~0 ± t α/2(n-2) SY~

Y~0= a+b X0

4 0
3 years ago
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