Answer:
Cost of equipment after n years = 300000 x 0.86ⁿ
Step-by-step explanation:
A construction company purchased some equipment costing $300,000.
Price of equipment = 300000 $
The value of the equipment depreciates (decreases) at a rate of 14% per year.
Let c(n) be the cost of equipment after n years.
Cost of equipment after n years = 300000 x 0.86ⁿ
2 - 2 * 0 ≤ 1
<span>2 ≤ 1 </span>
<span>4 - 2 * (-2) ≤ 1 </span>
<span>8 ≤ 1 </span>
<span>4 - 2 * (1) ≤ 1 </span>
<span>2 ≤ 1 </span>
<span>0 - 2 * 5 ≤ 1 </span>
<span>-10 ≤ 1 </span>
<span>(TRUE</span>
Answer:
(x+10)(x-10)
Step-by-step explanation:
both numbers can be squared so you have to take out the square and since 100 is negative one must be positive and one must be negative
Subtract 59 from both sides, you get x=-179
Answer:
$30 for 4 tickets $10.5 for 3 bags of popcorn and $4 for 2 sodas. Together the family will have to pay $44.5.
Step-by-step explanation:
