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Ksivusya [100]
3 years ago
7

In a football game, the Bobcats scored all touchdowns, which are worth 7 points each. The Crocodiles scored all field goals, whi

ch are worth 3 points each. Neither team went scoreless. The final score of the game was the lowest tie possible given these conditions. How many points did each team score?
Mathematics
2 answers:
Natalka [10]3 years ago
8 0

Answer: 21points

Step-by-step explanation: 3 times 7 equals 21

VashaNatasha [74]3 years ago
3 0

Answer:

21

Step-by-step explanation:

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Given the function f(x) = 2x, find the value of f−1(32). (1 point) f−1(32) = 0 f−1(32) = 1 f−1(32) = 5 f−1(32) = 16
lara31 [8.8K]

The value of the inverse function at x = 32 will be 16. Then the correct option is D.

<h3>What is a function?</h3>

A statement, principle, or policy that creates the link between two variables is known as a function.

The function is given below.

f(x) = 2x

Then the inverse function of the f(x) will be

2f⁻¹(x) = x

 f⁻¹(x) = x / 2

Then the value of the inverse function at x = 32 will be

f⁻¹(32) = 32 / 2

 f⁻¹(x) = 16

Then the correct option is D.

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

3 0
2 years ago
Polygon F has an area of 36 square units. Aimar drew a scaled version of Polygon F and labeled it Polygon G. Polygon G has an ar
mariarad [96]

Area is a squared number.  We know that from the label we use when we solve problems involving area.  Perimeter is a single unit label.  This single unit label can also be used to find scale factor, since single unit labels are one-to-one.  If the area of polygon F is 36, that means that the single unit measure was a number that was squared to get to the area.  Same goes for polygon G.  That means that in order to find the single unit measure of each of those we have to take the square root of the area.  The square root of 36 is 6, and the square root of 4 is 2.  6:2 is the scale factor, but that can be reduced to 3:1, larger to smaller.

6 0
3 years ago
Read 2 more answers
point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form
IRISSAK [1]

Answer:

4\sqrt{10}

Step-by-step explanation:

We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).

To find the length of segment AB we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Upon substituting coordinates of point A and point B in distance formula we will get,

\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}

\text{Distance between point A and point B}=\sqrt{(4)^2+(12)^2}

\text{Distance between point A and point B}=\sqrt{16+144}

\text{Distance between point A and point B}=\sqrt{160}

\text{Distance between point A and point B}=4\sqrt{10}

Therefore, the length of segment AB is 4\sqrt{10}.

3 0
3 years ago
PLEASE HELP ME I WILL GIVE YOU POINTS
Brilliant_brown [7]

Answer:I got 18.28

Step-by-step explanation:

so for getting the perimeter, you only need the outer line, so you sum the measurements you have for the rectangle: 1+2+2+7= 12. After that you need the circumference of the circle, you can figure it out by using the formula C = 2pi(r) You can find the radius by substracting the known sides of the rectangle attached to the circle from the bottom base and then dividing it in 2, leaving us with a radius of 2. Then we input values; C=2pi(2) which equals 4pi, but we need to divide that in half since it’s only half a circle. That leaves us with 2pi, or 6.28. Then we add the perimeter of the square, which was 12, and 6.28+12= 18.28

4 0
2 years ago
Solve the following system of equations. What is one x-value of a solution?
gulaghasi [49]

Answer:

There is some mistake in the question, because the solutions are x = -1.445 and x = -34.555

Step-by-step explanation:

Given the functions:

f(x) = x² + 4x + 10

g(x) = -32x - 40

we want to find the points at which f(x) = g(x).

x² + 4x + 10 = -32x - 40

x² + 4x + 10 + 32x + 40 = 0

x² + 36x + 50 = 0

Using quadratic formula:

x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}

x = \frac{-36 \pm \sqrt{36^2-4(1)(50)}}{2(1)}

x = \frac{-36 \pm 33.11}{2}

x_1 = \frac{-36 + 33.11}{2}

x_1 = -1.445

x_2 = \frac{-36 - 33.11}{2}

x_2 = -34.555

5 0
3 years ago
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