Answer:
The capacity of the disk is "40 GB".
Explanation:
Given value:







Cache memory is often used to speed up the runtime. It will enable us to improve performance unless we can store information, that is retrieved constantly in memory space.
- Hit Cache: when the Processor relates to representing database data, Cache Hit results.
- Miss Cache: when this Processor responds to a non-present cache data, this will trigger its miss of cache.
- It doesn't have to retrieve the Main Memory through secondary storage.
The picture that graphically represents the items you use in Windows or any other OS is called an Icon. An icon is a picture that represents the program that is being used. An icon is useful for the user's to directly know what type of program they need to use or such.
Answer:
1. G=D+(A+C^2)*E/(D+B)^3
cobegin:
p1: (D+B)
p2: p1^3
p3: C^2
p4: A+ p3
p5: E/p2
p6: p4 * p5
p7: D + p6
:G
coend
2. Now The value A=2, B=4, C=5, D=6, and E=8
p1: 6+4 =10
p2: p1 ^3= 10^3= 1000
p3: c^2= 5^2 =25
p4: A + p3= 2 +25 =27
p5: 8/1000
p6: 27 *8/1000
p7: D+ P6= 6+ 216/1000
= 6216/1000
=6.216
Explanation:
The above, first bracket with power is processed, and then power inside and outside bracket. And rest is according to BODMAS, and one process is solved at a time.