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Sidana [21]
3 years ago
14

What is the numerator of the simplified sum? OX+ 3 O 3x+6 O 4x+6 O 4x+2

Mathematics
1 answer:
Illusion [34]3 years ago
5 0
The correct answer is A
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The sum of two numbers is 19 . When the second number is subtracted from the first​ number, the difference is 17 . Find the two
zhenek [66]

Answer:

19 and 2

Step-by-step explanation:

Let x represent the first number and y represents second number

x + y = 19

x - y = 17 add two equations up

2x = 36 divide both sides by 2

x = 19 and since the difference is 17 the other number is 2

4 0
2 years ago
35,000 as a percent
Usimov [2.4K]
Move the deciaml 2 places to left

35000.
 move to the left 2 spots

350.00 so 350%
5 0
2 years ago
Read 2 more answers
Multiply.
Crank
The main rules that we use here are :

i) \sqrt{a \cdot b}=  \sqrt{a} \cdot \sqrt{b} for nonnegative values a and b.

ii) \sqrt{a} \cdot  \sqrt{a} =a.


Thus, first 'decompose' the numbers in the radicals into prime factors:

4 \sqrt{3} \cdot 10 \cdot  \sqrt{2\cdot2\cdot3}\cdot  \sqrt{2\cdot 3}\cdot  \sqrt{2}..

By rule (i) we write:

4 \sqrt{3} \cdot 10 \cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{\cdot3}\cdot \sqrt{2} \cdot  \sqrt{3} \cdot \sqrt{2}.

We can collect these terms as follows:

40 \sqrt{3}\cdot (\sqrt{3}\cdot \sqrt{3}) \cdot (\sqrt{2}\cdot \sqrt{2}) \cdot( \sqrt{2} \cdot \sqrt{2}), and by rule (ii) we have:

40 \sqrt{3}\cdot 3 \cdot 2 \cdot2=40\cdot12\cdot \sqrt{3}=480 \sqrt{3}.


Answer: 480 \sqrt{3}.
8 0
3 years ago
I really need the answer for this problem
morpeh [17]
The answer to your problem is 20%
3 0
3 years ago
Una empresa fabrica dos productos, X y Y. Cada cantidad del articulo X producida requiere dos horas de trabajo en una taladrador
Zarrin [17]

Answer:

la respuesta esta abajo

Step-by-step explanation:

a) Sea x el número del artículo x mientras que y representa el número del artículo y.

Dado que cada cantidad de artículo x requiere 2 horas de trabajo de perforación, mientras que cada cantidad de artículo y requiere 5 horas de trabajo de perforación. Hay un máximo de 40 horas disponibles, por tanto el modelo se da como:

2x + 5y ≤ 40

b) La trama se trazó utilizando la herramienta gráfica en línea de geogebra.

c) Para 10 unidades de X y 5 unidades de y:

2 (10) + 5 (5) = 45> 40

Por lo tanto, esto no sería posible porque requerirá 45 horas de perforación, lo que es más que el máximo de 40 horas disponibles.

8 0
3 years ago
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