$\bf [1-tan(\theta)][2sin(\theta)+1]=0\implies 
\begin{cases}
1-tan(\theta)=0\\\\
1=tan(\theta)\\\\
tan^{-1}(1)=\theta\\\\
\qquad \frac{\pi }{4},\frac{5\pi }{4}\\
----------\\
2sin(\theta)+1=0\\\\
2sin(\theta)=-1\\\\
sin(\theta)=\frac{-1}{2}\\\\
sin^{-1}\left(-\frac{1}{2} \right)=\theta\\\\
\qquad \frac{7\pi }{6},\frac{11\pi }{6}
\end{cases}$

3 0

4 years ago

Find marcRQT.<br> Honestly, I have no clue what I’m doing so please answer

maria [59]

Answer:

angels on a line add up to 180.

the angle opposite the 47 degrees is vertically opposite so that angle will be 47 degrees

180 - 47 - 55 = 78

78 + 55 = 133

angle qpu = 133 degrees

I'm not sure what Marc rqt means but hopefully the angles I have worked out help?

5 0

3 years ago