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3 years ago

36x - 63 = k(4x - 7) Need help, I dont know what im doing wrong here

Mathematics

1 answer:

ozzi3 years ago

6 0

Answer: k= 9

x= 7/4

Step-by-step explanation:

https://www.symbolab.com/solver/order-of-operations-calculator/36x%20-%2063%20%3D%20k%5Cleft(4x%20-%207%5Cright)

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In the expression 2a-5+4a-9, name the constants

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3 years ago

Find a ratio equivalent to 12/21 with lower terms

dmitriy555 [2]

Find factors of 12 and 21

Divide 3 from both numerator and denominator.

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3 years ago

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What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Ipatiy [6.2K]

Answer:

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

Step-by-step explanation:

$2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c = - 3 \\\\x = \frac{-b^2\ \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\$

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

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3 years ago

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3 years ago