Answer:
sinA(cosA+sinA)*cosA
Step-by-step explanation:
(sinA(2cosA+sinA-cosA))/secA
sinA(cosA+sinA)/secA
sinA(cosA+sinA)*cosA
Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
Summary of problem.
annual production = 60000 units
work hours per worker = 200*12=2400 hours
productivity = 0.15 unit / person-hour
Need to calculate the number of workers/persons employed.
Each unit requires 1 unit / 0.15 unit/person-hour
= 1/0.15 person-hours / unit
60000 unit requires 60000 units * 1/0.15 person-hours/unit
= 400000 person-hours
400000 person-hours requires 400000 person-hours /2400 hours = 166.7 persons
=>
The plant has 167 labourers (assuming perfect attendance).
