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JulsSmile [24]
3 years ago
11

Backpacks originally cost $24 but if 40% back to school sale is going on determine the sale price of the backpack.

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0

Answer: The price is now 14.40

Step-by-step explanation: The difference is 9.60

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Find the quotient and reduce to lowest terms: ((x²-4)/(3x)) ÷ ((x-2)/(2x)).
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Answer:   2/3 * (× + 2 )

Step-by-step explanation:

((x²-4)/(3x)) ÷ ((x-2)/(2x)).          ⇒   [ ( ײ - 4 ) * 2x ] ÷ [ ( × - 2 ) *3x ]

Simplifying by x   [ 2 * ( ײ - 4 ) ] ÷ [ ( × - 2 ) *3 ] ⇒ (2/3)*{ [ ( x-2 )*(×+2)]÷ (×-2) }

Simplifying by ( ×+2)     2/3 * (× + 2 )

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3 years ago
Please answer correctly show work and no links thanks!
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Answer: I think it is 12.375 ft

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Find the area of the rhombus in m squared
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Answer:

\boxed{\bold{100 \ m^2}}

Step By Step Explanation:

Area Of Rhombus: \bold{\frac{pq}{2} }

Identify 'p'

5 + 5 = 10

p = 10

Identify 'q'

10 + 10 = 20

q = 20

\bold{10 \ \cdot\ \ 20 \ = \ 200}

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➤ \boxed{\bold{Mordancy}}

4 0
2 years ago
Samuel is x year old and
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Answer:

Samuel : x

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3 years ago
Find the area of this regular polygon.<br> Round to the nearest tenth.<br> 8.65 mm<br> [? ]mm2
nadezda [96]

Answer:

Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:

a=√{b²+c²−2bc×cos40°}

a=√{149.645−149.645cos40°}

Area Nonagon = (9/4)a²cos40°

=9/4[149.645−149.645cos40°]cot20°

=336.70125[1−cos(40°)]cot(20°)

Applying an identity for the cos(40°) does not get us very far…

= 336.70125[1−(cos2(20°)−1)]cot(20°)

= 336.70125[2−cos2(20°)]cot(20°)

= 336.70125[2−(1−sin2(20°))]cot(20°)

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= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²

3 0
3 years ago
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