Help me please this is my last question
1 answer:
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<u>Answers:</u>
Two <u>triangles are congruent</u> if they have the <u>same sides</u> and the <u>same size</u>.
In other words: they have the same shape and size, regardless of their position or orientation.
If we want to verify if two triangles are congruent, they must fulfill some conditions:
a) Two triangles are congruent if their three sides are respectively equal
b) Two triangles are congruent if two of their sides and the angle between them are respectively of equal length.
c) Two triangles are congruent if they have a congruent side and the angles with vertex at the ends of that side are also congruent.
d) Two triangles are congruent if they have two sides respectively congruent and the angles opposite the greater of the sides are also congruent
<h2>According to these criteria, it is not necessary to verify the congruence of the three sides and three angles of each triangle </h2>
Now, knowing these criteria, let’s answer the questions:
1) Here both triangles are<u> congruent</u> and are <u>Right Triangles</u> (have a right angle or a angle), as well.
This means angle and according to the <u>criterion b</u> listed above, the angle
and angle
.
This can be proven by the rule that states the sum of the three interior angles of a triangle is .
Then, according <u>criterion a</u>, and
.
<u>This can be proven by the use of </u><u>two trigonometric functions,</u> sine and cosine:
<h2>
Where is the <u>Opposite side</u> to the
angle and
is the <u>hypotenuse</u>.
<h2>
≅6m
Where is the <u>Adjacent side</u> to the
angle and
is the <u>hypotenuse</u>.
<h2>Therefore, the answer is B: </h2>
,
,
,
,
2) According to the second figure shown, both triangles are congruent and fulfill the four criteria described above.
Therefore, the answer is:
<h2>CBA≅MPN</h2>
3) “Knowing that line segment AB is the same length as line segment CD is enough to prove that triangles ABD and BCD are congruent”
This statement is <u>True</u>, because <u>both triangles share the line segment BD</u>.
<h2>This means <u>they have two equal sides</u>, and according to <u>criterion b</u> they are congruent </h2>Answer:
V=25088π vu
Step-by-step explanation:
Because the curves are a function of "y" it is decided to take the axis of rotation as y
, according to the graph 1 the cutoff points of f(y)₁ and f(y)₂ are ±2
f(y)₁ = 7y²-28; f(y)₂=28-7y²
y=0; x=28-0 ⇒ x=28
x=0; 0 = 7y²-28 ⇒ 7y²=28 ⇒ y²= 28/7 =4 ⇒ y=√4 =±2
Knowing that the volume of a solid of revolution V=πR²h, where R²=(r₁-r₂) and h=dy then:
dV=π(7y²-28-(28-7y²))²dy ⇒dV=π(7y²-28-28+7y²)²dy = 4π(7y²-28)²dy
dV=4π(49y⁴-392y²+784)dy integrating on both sides
∫dV=4π∫(49y⁴-392y²+784)dy ⇒ solving ∫(49y⁴-392y²+784)dy
49∫y⁴dy-392∫y²dy+784∫dy =
V=4π( ) evaluated -2≤y≤2, or 2(0≤y≤2), also
⇒ V=25088π vu
