A rectangle has a perimeter of 80 cm and its length is 1 cm more than twice its width. Find the dimensions of a rectangle given
that its perimeter is 80 cm and its length is 1 cm more than twice its width. Set up your solution using the variables L for the length, W for the width, and P for the perimeter. Part a: Using the definition of the perimeter, write an equation for P in terms of L and W. Part b: Using the relationship given in the problem statement, write an equation for L in terms of W. Solve the equations from parts a and b. Part c: The length is ? Cm. Part d: The width is? Cm.
Theta = 210° r = 4.6/2 = 2.3 Area of circle = pi * r * r = 3.14 * 2.3 * 2.3 = 16.61 Area of sector = (theta / 360) * area of circle = (210/360) * 16.61 = 9.69
