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3 years ago

7

John buys 3 books that each cost the same amount and a magazine, all for $48.48. The magazine costs $1.98. How much does each bo

ok cost?

1 answer:

MakcuM [25]3 years ago

4 0

Answer:

15.50 per book

Step-by-step explanation:

48.48 - 1.98 (the magazine)

46.50

46.50/ 3

15.50 per book

Hope this helps!!!

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Simplify 5 n (15 - 2). <br> a.5n 13 <br> b.13n 5 <br> c.n 18

slava [35]

Answer: 5n 13, because you solve the quantity in parentheses first

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3 years ago

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I put it at 50 pts because it will take a while plz help me

makvit [3.9K]

Answer:

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3 years ago

How would you substitute this equation?

svlad2 [7]

If <em>y</em> = <em>x</em> and <em>y</em> = <em>z</em>, then by substitution we can say <em>x</em> = <em>z</em>.

In this case, substitution gives us

-1/2 <em>x</em> - 2 = -3/2 <em>x</em> + 2

and we can solve for <em>x</em> :

3/2 <em>x</em> - 1/2 <em>x</em> = 2 + 2

<em>x</em> = 4

then solve for <em>y</em> :

<em>y</em> = -1/2 <em>x</em> - 2

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3 years ago

Debi walks laps around the mall for exercise during the winter months. The table represents the number of steps recorded on her

MariettaO [177]

Answer:

<em>The correct option will be: b. One lap around the mall is equal to about 2,425 steps.</em>

Step-by-step explanation:

Here, we will just find <u>the slope of the line representing Debi’s data</u>. For that, we will take any two data from the table in form of point like $(x,y)$

Lets take two points as $(0, 1875)$ and $(2, 6725)$

<u>Formula for finding the slope</u> is: $m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two given points.

Here, $x_{1}= 0 , y_{1}= 1875 , x_{2}=2 , y_{2}=6725$

So, plugging these values into the above formula, we will get......

$m= \frac{6725-1875}{2-0}=\frac{4850}{2}=2425$

That means, one lap around the mall is equal to about 2,425 steps.

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3 years ago

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If z and w are complex numbers w = a+bi and z = c+di<br><br> Prove algebraically that |zw| = |z||w|.

-Dominant- [34]

Answer:

To show that $\lvert zw\rvert =\lvert z\rvert \lvert w\rvert$ observe that:

Step-by-step explanation:

We have that $w=(a+bi), z=(c+di)$ . Then $zw=(c+di)(a+bi)=(ac-bd)+(cb+ad)i$ . Now, the absolute value of this product is $\lvert zw \rvert =\sqrt{(ac-bd)^{2}+(cb+ad)^{2}}=\sqrt{a^{2}c^{2}-2acbd+b^{2}d^{2}+c^{2}b^{2}+2abcd+a^{2}d^{2}}=\sqrt{a^{2}c^{2}+b^{2}d^{2}+c^{2}b^{2}+a^{2}d^{2}}.$

On the other hand, $\lvert z\rvert =\sqrt{c^{2}+d^{2}}$ and $\lvert w \rvert =\sqrt{a^{2}+b^{2}}.$ Then,

$\lvert z\rvert \lvert w \rvert =\sqrt{c^{2}+b^{2}}\sqrt{a^{2}+b^{2}}=\sqrt{(c^{2}+d^{2})(a^{2}+b^{2})}=\sqrt{c^{2}a^{2}+c^{2}b^{2}+d^{2}a^{2}+d^{2}b^{2}}$

Then, it is clear that $\lvert zw \rvert =\lvert z\rvert \lvert w \rvert$ .

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4 years ago