Question

The value of (1-w) (1 -w^2), where w is the cube root of a complex number is

Answer 1

Answer:(1-w) (1-w*2)

=1-w*2-w+w*3

=1-w-w*2+1

=1-1+1

=1

Step-by-step explanation:

at first we should multiply them with each other

then, put the value of w*3 i.e. w*3=1

then, put the value of -w-w*2 i.e. 1

then, the final answer is 1.