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Cerrena [4.2K]
2 years ago
13

The value of (1-w) (1 -w^2), where w is the cube root of a complex number is

Mathematics
1 answer:
NeX [460]2 years ago
3 0

Answer:(1-w) (1-w*2)

=1-w*2-w+w*3

=1-w-w*2+1

=1-1+1

=1

Step-by-step explanation:

at first we should multiply them with each other

then, put the value of w*3 i.e. w*3=1

then, put the value of -w-w*2 i.e. 1

then, the final answer is 1.

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For what values of b the relation R:{(b^2, 5), (5b, 6)} is not a function?
xenn [34]

Answer:

B=5,0.

Step-by-step explanation:

It's not that hard. It's just that it might throw you off a bit with the R and the other things. Functions if you don't remember are where the coordinates don't have the same x and y. So since the y1 and y2 are different then to make it not a function, you have to make x1 and x2. To make it that b would have to be = to 5 and 0.

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3 years ago
The solid figure shown here can be formed from which net?​
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B

Step-by-step explanation:

If you unfold it you get shape B

5 0
3 years ago
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Does it matter term is first and which term is second in a ratio?
aleksklad [387]
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3 years ago
A sporting goods store sells 2 fishing reels and 4 fishing rods for $362. Later they sell 8 fishing reels and 2 fishing rods for
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7 0
3 years ago
1/2r -3= 3 (4-3/2r) solve for r
s2008m [1.1K]

1/2r -3= 3 (4-3/2r) is to be solved for r.


I'll begin by making the assumptions that by 1/2r you actually meant (1/2)r and that by 3/2r you actually meant (3/2)r. When in doubt, please use parentheses to make your meaning clear.


Thus, 1/2r -3= 3 (4-3/2r) becomes (1/2)r -3= 3 (4-(3/2)r ) .

Simplify this by multiplying all 3 terms by 2. Doing this will eliminate the fractions:


r -6 = 3 (4*2-(3)r ) or r - 6 = 24 - 9r


Now expand the right side, using the distributive property of

r - 3 = 24 - 9r


Regrouping so as to combine like terms:


10r = 30


Solving for r: r = 30/10 = 3


The value of r that satisfies this equation is 3

8 0
3 years ago
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