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STALIN [3.7K]
3 years ago
5

What is the slope between the points (-12,-5) and (0,8)

Mathematics
2 answers:
jenyasd209 [6]3 years ago
5 0

Answer:

The slope between the points (-12,-5) and (0,8) is 13/12 .

Step-by-step explanation:

We have two points which are ( -12 ,-15 ) and ( 0,8).

To find the slope between the points (-12,-5)and (0,8) we using slope formula which is

  • m = ( y ² - y ¹ ) / ( x ² - x ¹)

Where,

  • m , is the slope
  • ( y ² - y ¹ ) = ( -12 , - 5)
  • ( x ² - x ¹) = ( 0,8 )

Substitute the values into the formula

m = ( 8 - ( -5 ) / ( 0 - ( - 12 )

m= ( 8 + 5 ) / ( 0 + 12 )

m = 13 / 12

Therefore ,13/12 is the slope between the points (-12,-5) and (0,8)

DIA [1.3K]3 years ago
3 0

Answer:

13/12

Step-by-step explanation:

We can use the slope formula when we have two points

m= ( y2-y1)/(x2-x1)

   = ( 8- -5)/(0 - -12)

   = (8+5)/(0+12)

   = 13/12

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(Crys) Im in 11 grade and in applied geometry I need help crys and how do you show
Snowcat [4.5K]

Answer:

1. -2/3        3. -5/4         5. 3/2          FOR THE REST OF THE PARTS LOOK THROUGH THE EXPLANATIONS

Step-by-step explanation:

Before I start the workings, I'll give a little explanation on this topic.

So, the equation of a straight line is

y = mx + c

where x and y are any coordinates of any point on the line.

m is the gradient or slope

m can be calculated using 2 formulas,

formula 1: Rise/Run

where rise is the how much a graph goes upwards or downwards, if its upwards use positive integer and if its downwards use negative integer.

Run is how much a graph moves to the right or to the left, if it moves to the right is is positive, if it moves to the left it is negative.

Formula 2: (y2-y1)/(x2-x1)

the values of these are taken through any 2 coordinates on the line.

and c is the y-intercept(the point where the line crosses the y-axis.

<u>MOVING TO ANSWERING NOW</u>

1. Dotted points on the line are (1,0) and (4,-2)

Formula of slope,

U can use any of the 2 formulas given above

I'll show both for this question

m = (y2-y1)/(x2-x1) = (-2-0)/(4-1) = -2/3

OR

m = rise/run = where rise is -2 and run is 3 so -2/3

2. TRY DOING THIS ONE YOURSELF

For the next part I'll do 3 and 5 for your understanding, try doing 2 and 4 on your own to understand.

3. Coordinates given (13,1) and (1,16)

m = (y2-y1)/(x2-x1) = (16-1)/(1-13) = 15/-12  simplify this and it becomes -5/4

5.  (-8,-14) and (-10,-17)

m =  (y2-y1)/(x2-x1) = (-17-(-14))/(-10-(-8)) = -3/-2 = 3/2

FOR THE NEXT PART I'LL DO 7,8 AND 10 FOR YOU, TRY DOING 9 ON YOUR OWN FOR PRACTICE.

I WILL ALSO ATTACH FILES FOR THE NEXT PARTS IN ORDER OF QUESTIONS SO SEE THEM.

7. y = x + 3 this means y = 1x +3 which means:

1 is the gradient

3 is the y-intercept

so 1 as a fraction is 1/1 which means rise is one upwards and run is 1 to the right.

Now go to the graph on the y-axis and plot the point 3, (0,3) is your y-intercept. From their rise by one and run by one this will lead u to point (1,4)

Mark both these points and make a line through them.

8. x = -5

now look at this equation in the form of y = mx + c

0 = 1x + 5 the means y is 0 and it is already told in the question that x = -5

if u rearrange 0 = 1x + 5 it will give you x = -5

now when y is  0 x = -5 put a point on the coordinate (-5,0) and draw a vertical straight line.

10. y = (1/4)x - 1

slope is 1/4 which means rise is 1 and run is 4

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now go to y=-1 which is the coordinate (0,-1) and rise by one and run by 4, this will take u to the coordinate (4,0) now put a dot on both coordinates, connect them and put a line through them.

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