Answer:
Here, the given problem,
The total number of hours =
Now, the number of hours to make each invitation card =
Hence, the total number of invitations =
a. Scale the number line from 0 to 1,
In which each unit represents
By the number line,
b. By model,
Take a grid which shows 1 hour and each box of the grid represents 1/12th hour,
By the grid,
That is, the number of hours to make invitation = 9
c.
Answer: A B
Group 1 0.25 0.75
Group 2 0.44 0.56
Step-by-step explanation:
Since we have given that
Number of people of A in group 1 = 15
Number of people of B in group 1 = 45
Total number of people in group 1 is given by
Relative frequency of people of A in Group 1 is given by
Relative frequency of people of B in Group 1 is given by
Similarly, Number of people of A in group 2 = 20
Number of people of B in group 2 = 25
Total number of people in group 2 is given by
Relative frequency of people of A in Group 2 is given by
Relative frequency of people of B in Group 2 is given by
Hence, A B
Group 1 0.25 0.75
Group 2 0.44 0.56
A/b=c
b=ac
:-):-):-) I hope this helped
Answer:
H0: p1=p2 against the claim Ha: p1≠p2
Step-by-step explanation:
Here the proportion of the people going for medical checkup before the program is p1= 0.76
The proportion of the people going for medical checkup after the program is p2= 686/880=0.78
Our null and alternate hypothesis will be
H0: proportion of the people going for medical checkup before the program <u>is equal </u>to the proportion of the people going for medical checkup after the program
against the claim
Ha: proportion of the people going for medical checkup before the program <u>is not equal </u>to the proportion of the people going for medical checkup after the program
Mathematically this can be written as
H0: p1=p2 against the claim Ha: p1≠p2
Alliteration because pours and potions both have p's (i'm pretty sure)