Answer:
4X + 30 = TOTAL AMOUNT OF MONEY
Step-by-step explanation:
All of them bought a ride ticket (that explains the 4x)
3 of them also bought a game pass thet costs $10 each. That explains the 30
<em>going deeper</em>: If the total amount of money was $70
The tickets would've costed $10 each.
Look:
4x + $30 = $70
4x = 70 - 30
4x = 40
x = 40/4
x =$10
Answer:
A, B, D
Step-by-step explanation:
A) -15(4x + 3) = -15 · 4x + (-15) · 3 = -60x - 45
B) 3(-20x - 15) = -60x -45
C) 5(12x - 9) = 60x - 45
D) -5(12x + 9) = -60x - 45
Answer:
2 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Using the normal distribution, there is a 0.007 = 0.7% probability that the mean score for 10 randomly selected people who took the LSAT would be above 157.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
Researching this problem on the internet, the parameters are given as follows:
![\mu = 150, \sigma = 9, n = 10, s = \frac{9}{\sqrt{10}} = 2.85](https://tex.z-dn.net/?f=%5Cmu%20%3D%20150%2C%20%5Csigma%20%3D%209%2C%20n%20%3D%2010%2C%20s%20%3D%20%5Cfrac%7B9%7D%7B%5Csqrt%7B10%7D%7D%20%3D%202.85)
The probability is <u>one subtracted by the p-value of Z when X = 157</u>, hence:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
By the Central Limit Theorem
![Z = \frac{X - \mu}{s}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7Bs%7D)
Z = (157 - 150)/2.85
Z = 2.46
Z = 2.46 has a p-value of 0.993.
1 - 0.993 = 0.007.
0.007 = 0.7% probability that the mean score for 10 randomly selected people who took the LSAT would be above 157.
More can be learned about the normal distribution at brainly.com/question/15181104
#SPJ1
X = 7/2 or 3 1/2
2x + 5 =12
-5 -5
——————
2x = 7
—- —
2 2