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GenaCL600 [577]
3 years ago
15

Help is needed please hurry

Mathematics
1 answer:
denpristay [2]3 years ago
4 0

Step-by-step explanation:

step 1. Where is the original equation? let's assume it is y = x^2

step 2. to shift to the right 3 places replace x with x - 3 and to shift 4 down subtract 4 from the equation

step 3. y = (x - 3)^2 - 4.

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Which polynomial expression represents the area of the outer most square tile, shown below?
Andrew [12]

ANSWER

{x}^{2}  - 6x + 9

EXPLANATION

The outermost square tile has side length,

l = x - 3

The area of a square is given by;

Area= {l}^{2}

We substitite the given expression for the side length into the formula to obtain,

Area= {(x - 3)}^{2}

Area= {(x - 3)}(x - 3)

We expand using the distributive property to obtain;

Area=x {(x - 3)} - 3(x - 3)

This gives us:

Area= {x}^{2}  - 3x - 3x  + 9

Area= {x}^{2}  - 6x + 9

The last choice is correct.

7 0
3 years ago
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Pls help w math !
Vsevolod [243]
The answer is -7
4+-7=-3
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Please Help !!! If F(x)=x-7 and G(x)=x³, what is G(F(x))
Masteriza [31]

(x-7)^3 should be the correct answer.

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3 years ago
Find the square root of 64a^2/9b^2+4+32a/3b​
insens350 [35]

Answer:

the square root of 64a^2/9b^2+4+32a/3b is

  • ( 8a + 6b ) / 3b

or

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8 0
3 years ago
If you roll two six-faced dice together, you will get 36 possible outcomes. 4 pts 1. List all possible outcomes of the experimen
bezimeni [28]

Given:

Two dice are rolled together.

Total number of possible outcomes.

To find:

The list of total possible outcomes.

The probability of getting a sum of 11 in these outcomes.

The probability of getting a sum less than or equal to 4.

The probability of getting a sum of 13 or more.

Solution:

If two dice are rolled together, then the total number of possible outcomes is 36 and list of total possible outcomes is

S = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Sum of 11 in these outcomes = {(5,6),(6,5),(6,6)} = 3

The probability of getting a sum of 11 in these outcomes is

P(\text{sum=11})=\dfrac{3}{36}

P(\text{sum=11})=\dfrac{1}{12}

Therefore, the probability of getting a sum of 11 in these outcomes is \dfrac{1}{12}.

Sum less than or equal to 4 = {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)} = 6

The probability of getting a sum less than or equal to 4 is

P({sum\leq 4})=\dfrac{6}{36}

P({sum\leq 4})=\dfrac{1}{6}

Therefore, the probability of getting a sum less than or equal to 4 is \dfrac{1}{6}.

Sum of 13 or more = empty set because maximum sum is 12.

The probability of getting a sum of 13 or more is

P(sum\geq 13)=\dfrac{0}{36}

P({sum\geq 13})=0

Therefore, the probability of getting a sum of 13 or more is 0.

8 0
3 years ago
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