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4 years ago

The difference between the roots of the quadratic equation x2−8x+p=0 is 6. Find p.

Mathematics

1 answer:

Eduardwww [97]4 years ago

7 0

Answer:

p=7

Step-by-step explanation:

x1+x2=8

2x+6=8

2x=2

x=1

c/a=c

x1*x2=c=p

x1*x2=7

p=7

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In a scalene triangle , the perimeter is 33, and the length of one side is 15, and the difference between the two other sides is

zepelin [54]

Answer:D

Step-by-step explanation:

4 0

3 years ago

Solve this system by elimination. 3x+4y=5 -5x-4y=-11

ehidna [41]

3x + 4y = 5
-5x - 4y = -11
 -2x = -6
 -2x = -6
 -2 -2
 x = 3
3(3) + 4y = 5
 9 + 4y = 5
 -9 -9
 4y = -4
 4y = -4
 4 4
 y = -1
 (x, y) = (3, -1)

3 0

4 years ago

Read 2 more answers

I need help plss!! I don’t understand

MA_775_DIABLO [31]

Since it says what the area of the circle is, you need to work the problem backwards from finding the area. So it would be 100 ÷ 3.14 = 31.84 that is the radius. Next you need to find the diameter, so 31.84 × 2 = 63.68. Now you multiply 63.68 × 3.14 = 199.95, round that to 200, divide 200 ÷ 2 = 100 ÷ 2 = 50 miles

Answer= 50 miles

4 0

3 years ago

A triangle has side lengths of (7x-4)(7x−4) centimeters, (x+3)(x+3) centimeters, and (3y+2)(3y+2) centimeters. Which expression

Papessa [141]

Answer:

This assumes that the question was meant to read:

"A triangle has side lengths of (7x−4) centimeters, (x+3) centimeters, and (3x+2) centimeters." And not "A triangle has side lengths of (7x-4)(7x−4) centimeters, (x+3)(x+3) centimeters, and (3y+2)(3y+2) centimeters."

If the revision is correct, the perimeter is 11x + 1 cm

=============================================

If the question was correctly written, then answer is:

50x^2 - 50x + 9y^2 + 12 y + 29

===============

Step-by-step explanation:

(7x-4) cm

+ (x+3) cm

+ (3x+2) cm

11x + 1 cm

If the question was correctly written as is, then:

(7x-4)(7x−4) = 49x^2 - 56x + 16

+(x+3)(x+3) = + x^2 + 6x + 9

+(3y+2)(3y+2) = +9y^2 + 12 y + 4

50x^2 - 50x + 9y^2 + 12 y + 29 cm

8 0

3 years ago

A high school basketball game between the Raiders and the Wildcats was tied at the end of the first quarter. The number of point

AnnyKZ [126]

Answer: 5 and 14.

Step-by-step explanation:

We know that the Raiders and Wildcats both scored the same number of points in the first quarter so let a,a+d,a+2d,a+3d be the quarterly scores for the Wildcats. The sum of the Raiders scores is a(1+r+r^{2}+r^{3}) and the sum of the Wildcats scores is 4a+6d. Now we can narrow our search for the values of a,d, and r. Because points are always measured in positive integers, we can conclude that a and d are positive integers. We can also conclude that $r$ is a positive integer by writing down the equation:

a(1+r+r^{2}+r^{3})=4a+6d+1

Now we can start trying out some values of r. We try r=2, which gives

15a=4a+6d+1

11a=6d+1

We need the smallest multiple of 11 (to satisfy the <100 condition) that is 1 (mod 6). We see that this is 55, and therefore a=5 and d=9.

So the Raiders' first two scores were 5 and 10 and the Wildcats' first two scores were 5 and 14.

4 0

3 years ago