\dfrac15(15+10k) = 5 1 (15+10k)
1 answer:
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To find:
Any two quadratic equations.
Solution:
The general form of a quadratic equation is:
Where, a,b and c are real number and a is non zero.
We know that a,b,c can take any values but a cannot be 0.
For a=1, b=1,c=1, we get
One quadratic equation is .
For a=3,b=-1,c=5, we get
Therefore, the two quadratic equations are and
.
Answer:
(√3)/2 -1 ≈ -0.133974596
Step-by-step explanation:
2sin²(30°)tan(60°) -3cos²(60°)sec²(30°)
= 2(1/2)²(√3) -3(1/2)²(2/√3)²
= 2(1/4)√3 -3(1/4)(4/3)
= (√3)/2 -1 ≈ -0.133974596
