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Aliun [14]
3 years ago
12

Find the inverse of the function f (x) = 15 + sqrt 5x - 5

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

15 +  \sqrt{5x - 5}  = f(x)

Replace y for x and vice versa

15 +  \sqrt{5y - 5}  = x

Solve for y.

15 + 5y - 5 =  {x}^{2}

15 + 5y =  {x}^{2}  + 5

5y =  {x}^{2}  - 10

y =  \frac{ {x}^{2} - 10 }{5}

f {}^{ - 1} (x) =  \frac{ {x}^{2} - 10 }{5}

If

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A certain article reported the following observations, listed in increasing order, on drill lifetime (number of holes that a dri
aleksklad [387]

Answer:

Sample mean =119.42

Median = 92

25% trimmed mean = 102.42

10% trimmed mean = 95.69

Step-by-step explanation:

Data in increasing order :

12 13 20 23 31 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249 262 289 323 388 513

Total no. of observations = 50

Sample mean = \frac{\text{Sum of all observations}}{\text{Total number of observations}}

= \frac{5971}{50} = 119.42

Median: Since we have even number of observation

Median = \frac{1}{2}({25\text{th term} + 26\text{th term}) = \frac{91+93}{2} = 92

10% Trimmed Mean: We remove 5 values from each side

Trimmed set = 35 40 43 48 49 58 62 66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141 147 159 161 168 183 207 249

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{4097}{40} = 102.42

25% Trimmed Mean: We remove 12 values from each side.

Trimmed set =  66 67 69 71 73 77 78 79 82 85 86 89 91 93 97 99 101 105 106 106 112 117 124 135 139 141

Trimmed mean =  \frac{\text{Sum of Trimmed Set}}{\text{Total number of observations}} = \frac{2488}{26} = 95.69

6 0
3 years ago
I need an answer!! (marking as brainliest)
irina1246 [14]

Answer: I hope this helps.

Step-by-step explanation:

5 0
1 year ago
A plant grows 3 centimeters in 10 days. How much does it grow per day?
andreyandreev [35.5K]
Simple, .3 centimeters a day. 

3/10=.3
6 0
3 years ago
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The table shows the concentration of a reactant in the reaction mixture over a period of time.
saveliy_v [14]
<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: 2.0 \times 10^{-3}</h3>

<em><u>Solution:</u></em>

Average rate is the ratio of concentration change to the time taken for the change

Average\ rate = \frac{ \triangle c }{\triangle t }

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}

Thus option C is correct

5 0
4 years ago
6. Find the sum or difference.<br> (69 - 3) - (4g + 5)
serg [7]

Answer:

61-4g

Step-by-step explanation:

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8 0
3 years ago
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