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Anna71 [15]
3 years ago
9

Help, i dont know any of this lol

Mathematics
1 answer:
ale4655 [162]3 years ago
7 0

Answer:

18m³ + 2m² – m

Combine (add and subtract) the terms that have the same variable and exponent. Do not combine terms that have different exponents or variables.

5m³ +5m³ + 8m³ = 18m³

3m² +3m² –4m² = 2m²

–2m –2m +3m = –m

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The equation for the circle below is the x2 + y2=81. what is the length of the circles radius
larisa [96]

Answer:

9

Step-by-step explanation:

Compare your x2 + y2=81 to the following:

                       x^2 + y^2 = 81

The " ^ " symbol indicates exponentiation.

Now compare  x^2 + y^2 = 81 to

                         x^2 + y^2 = r^2.  

This is the standard equation of a circle of radius r centered at the origin, (0,0).  You can see for yourself that 81 must equal r^2.


Taking the square root of 81, we get plus or minus 9.

But the radius must be positive, so we reject the -9 and take +9.

The radius is 9.

8 0
3 years ago
Read 2 more answers
1+1-1......................help plz due in 20 secs
kap26 [50]

1 is ur answer Step-by-step explanation:

4 0
3 years ago
Find the line through (3, 1, −2) that intersects and is perpendicular to the line x = −1 + t, y = −2 + t, z = −1 + t. (HINT: If
mel-nik [20]

Answer:

( xo , yo , zo ) = ( 1 , 0 , 1 )

Step-by-step explanation:

Given:-

- A line passing through point (3, 1, −2) intersects and is perpendicular to line with coordinates:

                  x = −1 + t, y = −2 + t, z = −1 + t   .... t = arbitrary parameter.

Find:-

The coordinates for point of intersection.

Solution:-

- The line that passes through point (3, 1, −2) = ( a, b , c ) and an a arbitrary point on the given line have the following direction vector d2 :

                 d2 = ( x2 , y2 , z2 )

                 x2 = a - ( x ) = 3 - ( -1 + t ) = 4 - t

                 y2 = b - ( y ) = 1 - ( -2 + t ) = 3 - t

                 z2 = c - ( z )  = -2 - ( -1 + t ) = -1 - t

                d2 = (  4 - t , 3 - t , -1 - t )

- The direction vector d1 of the given line is:

                 d1 = ( x1 , y1 , z1 )

                 x1 = 1

                 y1 = 1

                 z1 = 1

                 d1 = ( 1 , 1 , 1 )

- The dot product of two orthogonal vectors is always equal to zero:

                 d1.d2 = 0

                 (  4 - t , 3 - t , -1 - t ) . ( 1 , 1 , 1 ) = 0

- Solve for parameter (t):

                 (4 - t) + (3 - t) + (-1 - t) = 0

                  6 -3t = 0

                  t = 2  

- The coordinates of the point of intersections can be evaluated by substituting the value of "t" into the given equation of line:

                 xo ( t = 2) = - 1 + 2 = 1

                 yo ( t = 2) = - 2 + 2 = 0

                 zo ( t = 2) = - 1 + 2 = 1

- The coordinates are:

                 ( xo , yo , zo ) = ( 1 , 0 , 1 )

8 0
3 years ago
The perimeter of a square is 36 feet. If you increase the length by 3 feet and decrease the width
Rufina [12.5K]

Answer:

84 feet

Step-by-step explanation:

If the perimeter is 36 feet, and all the sides are the same length, then all the sides are 9. if we increase the length by 3 feet and decrease the width  by 2 feet then we are left with 12 * 7 = 84

4 0
3 years ago
ABC is a tangent to the circle below. O is the centre of the circle. Work out the size of angle 0. Give reasoning to justify you
Delvig [45]

Answer:

Θ = 46°

Step-by-step explanation:

the angle between a tangent and a radius at the point of contact is 90° , so

∠ ABO = 90°

since OB = OD ( radii of circle ) then Δ BOD is isosceles and

∠ OBD = ∠ ODB = 22°

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ AOB is an exterior angle of the triangle , then

∠ AOB = 22° + 22° = 44°

the sum of the 3 angles in Δ AOB = 180° , then

Θ + 44° + 90° = 180°

Θ + 134° = 180° ( subtract 134° from both sides )

Θ = 46°

6 0
2 years ago
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