9514 1404 393
Answer:
1. proportional, 6
2. not proportional
Step-by-step explanation:
<u>Table 1</u>
Each y-value is 6 times the corresponding x-value, so the variables are proportional, and y = 6 times x.
<u>Table 2</u>
The ratios of y to x are 2, 4, 8, so are not the same. The values are not proportional.
Step-by-step explanation:
Left hand side:
4 [sin⁶ θ + cos⁶ θ]
Rearrange:
4 [(sin² θ)³ + (cos² θ)³]
Factor the sum of cubes:
4 [(sin² θ + cos² θ) (sin⁴ θ − sin² θ cos² θ + cos⁴ θ)]
Pythagorean identity:
4 [sin⁴ θ − sin² θ cos² θ + cos⁴ θ]
Complete the square:
4 [sin⁴ θ + 2 sin² θ cos² θ + cos⁴ θ − 3 sin² θ cos² θ]
4 [(sin² θ + cos² θ)² − 3 sin² θ cos² θ]
Pythagorean identity:
4 [1 − 3 sin² θ cos² θ]
Rearrange:
4 − 12 sin² θ cos² θ
4 − 3 (2 sin θ cos θ)²
Double angle formula:
4 − 3 (sin (2θ))²
4 − 3 sin² (2θ)
Finally, apply Pythagorean identity and simplify:
4 − 3 (1 − cos² (2θ))
4 − 3 + 3 cos² (2θ)
1 + 3 cos² (2θ)
A) is 0.83 and idk how to do b)
Median mean to find the center of the data
Circumference = 2pi * r
So
3pi = 2pi r divide away pi
3 = 2 r
(3/2) = r = 1.5 m
Area = pi ( r^2) = pi (1.5)^2 = 2.25 pi m^2 ≈ 7.07 m^2
cited from web2.0calc
