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Anton [14]
2 years ago
6

George has baked 48 chocolate chip cookies and 64 snickerdoodle cookies

Mathematics
1 answer:
hoa [83]2 years ago
3 0

Answer:

sorry i just needs pointso k ok

Step-by-step explanation:

but yea fien the answer is

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Can someone tell me what i did wrong cuz it’s wrong please will name brainliest
valkas [14]
Switch 2 units to 5 units.

Explanation:

If Figure G was a reflection over the x-axis (which it is), then the bottom right angle would be at 4 on the y axis. In order for it to get to -1, you would need to move Figure G down 5 units. I hope this helps!
4 0
2 years ago
Read 2 more answers
A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
Shalnov [3]

Answer:

We conclude that the true average percentage of organic matter in such soil is different from 3%.

Step-by-step explanation:

We are given that the values of the sample mean and sample standard deviation are 2.481 and 1.616, respectively.

Suppose we know the population distribution is normal, we have to test the hypothesis that does this data suggest that the true average percentage of organic matter in such soil is something other than 3%.

<em>Let </em>\mu<em> = true average percentage of organic matter in such soil</em>

SO, <u>Null Hypothesis</u>, H_0 : \mu = 3%   {means that the true average percentage of organic matter in such soil is equal to 3%}

<u>Alternate Hypothesis</u>, H_A : \mu \neq 3%   {means that the true average percentage of organic matter in such soil is different than 3%}

The test statistics that will be used here is <u>One-sample t test statistics</u> because we don't know about the population standard deviation;

                           T.S.  = \frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }  ~ t_n_-_1

where,  \bar X = sample mean amount of organic matter = 2.481%

              s = sample standard deviation = 1.616%

              n = sample of soil specimens = 30

So, <u><em>test statistics</em></u>  =  \frac{0.02481-0.03}{{\frac{0.01616}{\sqrt{30} } } }  ~ t_2_9

                               =  -1.759

<u></u>

<u>Now, P-value of the test statistics is given by;</u>

       P-value = P( t_2_9 > -1.759) = <u>0.046</u> or 4.6%

  • If the P-value of test statistics is more than the level of significance, then we will not reject our null hypothesis as it will not fall in the rejection region.
  • If the P-value of test statistics is less than the level of significance, then we will reject our null hypothesis as it will fall in the rejection region.

<em>Now, here the P-value is 0.046 which is clearly smaller than the level of significance of 0.05 (for two-tailed test), so we will reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the true average percentage of organic matter in such soil is different from 3%.

3 0
3 years ago
4. A number increased by 9 is equal to -44.
wariber [46]

x + 9 = -44

1. Subtract 9 to both sides

x = -53

5 0
2 years ago
Read 2 more answers
Which of the following represents the slope and y-intercept of the line?
Luba_88 [7]

Answer:

try hard

Step-by-step explanation:

7 0
3 years ago
Wayne went on a 4km hike. He took a break at 4/3 k. He took a drink of water at 10/3. Show Wayne's hike on the number line. Incl
tamaranim1 [39]
1. The information given in this problem, is:
 
 - <span>Wayne went on a 4 km hike.
 - </span>Wayne took a break at 4/3 km.
 - Wayne took a drink of water at 10/3.
 
 2. Then, when you convert the values from fractions to decimals, you have:
 
 4/3 km=1.33 km
 10/3 km=3.33 km
 
 3. With this values, you can make the number line and show <span>his starting and finishing place, and the 2 points where he stopped. This is shown in the figure attached.</span>

6 0
3 years ago
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