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2 years ago

George has baked 48 chocolate chip cookies and 64 snickerdoodle cookies

Mathematics

1 answer:

hoa [83]2 years ago

3 0

Answer:

sorry i just needs pointso k ok

Step-by-step explanation:

but yea fien the answer is

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HELPPP!!!!!!!!!!!!!!!!

Neko [114]

Answer:

Step-by-step explanation:

Because of the exponent in x²

5 0

2 years ago

I need to simplify this complex fraction

vovangra [49]

I see two ways to do it.

First, you have to understand that when you see a 'complex fraction' like this, the top number is a numerator, and the two bottom numbers are both denominators.

Way-1:

Take the top fraction . . . 2/2 . That's equal to 1 . So the whole thing is 1/3.

Way-2:

Multiply the bottom two denominators. Then the whole thing is 2/(2·3) . That's the same thing as 2/6 . Simplify that, and you have 1/3 .

7 0

3 years ago

Please help please these are short answers

atroni [7]

Answer: The answers are given below.

Step-by-step explanation: The calculations are as follows:

(19) Weight of the puppy last week is

$W_\ell=2\dfrac{1}{2}~\textup{lb},$

and weight of the puppy this week is

$W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.$

Therefore, the weight gained by the puppy is given by

$W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.$

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

$H_\ell=\dfrac{4}{9}~\textup{hr},$

and the time taken by Nazia to complete her Mathematics homework is

$H_m=\dfrac{2}{9}~\textup{hr}.$

Therefore, Nazia takes more time to complete Language Arts homework, by

$H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.$

(22) Quantity of Aluminium collected by Maya is

$A_m=\dfrac{4}{20}=0.2~\textup{lb},$

and the quantity of Aluminium collected by her friend Abigail is

$A_a=\dfrac{7}{8}=0.87~\textup{lb}.$

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

$T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.$

(23) Quantity of snow fall last Wednesday is

$S_w=3\dfrac{1}{4}=3.25~\textup{in.},$

and quantity of snowfall on sunday is

$S_s=3\dfrac{4}{5}=3.8~\textup{in.}.$

Therefore, quantity of snowfall was more on Sunday by

$S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.$

Thus, all the questions are answered.

3 0

3 years ago

At a pet store, one fifth of the animals are cats and three-fourth are fish. There are 40 animals at the pet store. How many are

dybincka [34]

Answer:

2 animals

Step-by-step explanation:

Number of animals=40

Fraction of fish=3/4

=>number of fish=3/4*40=30

Fraction of cats=1/5

=>number of cats=1/5*40=8

Animals which are not cats or fish are=total number of animals-(number of cats + number of fish)

Animals which are not cats or fish=40-(8+30)

40-38

2 animals

7 0

3 years ago

Solve for x and y y=6+3x x+y=110

mart [117]

Answer: x=1/3y−2

y=−x+110

Step-by-step explanation:

3 0

3 years ago

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